materials and their working properties
4 detailed 50-minute lessons with teaching scripts, worked examples, parent guides, and assessment criteria.
4 detailed 50-minute lessons with teaching scripts, worked examples, parent guides, and assessment criteria.

Write down everything you already know about materials and their working properties. Then check against the key terms: D&T Exam Tips. Use a mini-whiteboard or paper.
Start with the revision notes summary, then attempt: Explain the difference between hardness and toughness, giving an example of a material that is hard but not tough.
Your student states one thing they learned and one question they still have about materials and their working properties.
Quick recap: write 3 key points from Lesson 1 on materials and their working properties. Check them against the notes below.
| Term | Meaning | Example |
|---|---|---|
| Tensile strength | Resistance to pulling apart | Tensile test machine |
| Compressive strength | Resistance to crushing | Compression test |
| Hardness | Resistance to surface scratching | Vickers/Brinell test |
| Toughness | Energy absorption before fracture | Impact (Izod/Charpy) |
| Ductility | Ability to be drawn into wire | Elongation test |
| Density | Mass per unit volume (kg/m3) | Measure mass/volume |
Q: Explain the difference between hardness and toughness, giving an example of a material that is hard but not tough.
Answer: Hardness = resistance to surface deformation/scratching. Toughness = ability to absorb impact energy without fracturing. Glass is hard (resists scratching) but not tough (shatters on impact). In contrast, rubber is not hard (easily scratched) but is tough (absorbs impact energy without breaking).
Your student teaches the key points back to you without looking. Fill any gaps immediately.
Recall the key terms: D&T Exam Tips. Define each in one sentence.
Q1: Explain the difference between hardness and toughness, giving an example of a material that is hard but not tough.
Answer: Hardness = resistance to surface deformation/scratching. Toughness = ability to absorb impact energy without fracturing. Glass is hard (resists scratching) but not tough (shatters on impact). In contrast, rubber is not hard (easily scratched) but is tough (absorbs impact energy without breaking).
Q2: A designer needs a material for electrical wiring. Justify the choice of copper over steel based on working properties.
Answer: Copper: excellent electrical conductivity (second only to silver), ductile (easily drawn into wire), malleable (easy to bend during installation), corrosion resistant (forms protective patina). Steel: poor conductivity, less ductile (harder to draw and bend), heavier, prone to rust. Copper is chosen for its combined conductivity and workability despite being more expensive than steel.
Q3: Why is brittleness an important consideration when selecting materials for a car bumper?
Answer: A car bumper must absorb impact energy without shattering — it needs toughness, not hardness. A brittle material (e.g. rigid plastic or ceramic) would crack on impact, failing to protect the vehicle and creating sharp debris. Modern bumpers use tough polymers (polypropylene, polycarbonate blends) that deform to absorb energy then spring back.
Review any questions answered incorrectly. Identify whether the error was knowledge, method, or reading the question.
Review what these command words require: state (one point), describe (say what happens), explain (say why), compare (both sides), evaluate (judgement).
Extended question: Full-Mark Response Compare the suitability of mild steel and polycarbonate for a child's bicycle helmet shell, considering at least four working properties. <div class="
A grade 9 response will: identify helmet requirements (impact protection, lightweight, comfort, durability); compare properties — Toughness: polycarbonate is extremely tough (absorbs impact, deforms without shattering); mild steel is tough but dents permanently. Weight/density: polycarbonate approx 1.2 g/cm3; mild steel approx 7.8 g/cm3 — steel helmet would be unbearably heavy. Malleability: polycarbonate can be vacuum-formed into complex shell shapes; steel requires stamping with limited formability. Corrosion: polycarbonate is inert; steel rusts unless coated. Conclusion: polycarbonate is far superior for this application due to its combination of toughness, low density, formability and corrosion resistance.
You are ready for materials and their working properties - GCSE Design and Technology Lessons when you can:
Tick each item honestly — if any box is unticked, re-read the relevant section above.
How examiners mark materials and their working properties - GCSE Design and Technology Lessons: Read the command word carefully — State = one word/phrase (1 mark), Describe = pattern or detail (2 marks), Explain = reason with "because" (2–3 marks), Compare = similarities AND differences, Evaluate = both sides + conclusion. Method marks are awarded for correct working even if the final answer is wrong. Always show your working — unexplained answers score zero for AO2.
Success on materials and their working properties - GCSE Design and Technology Lessons questions: Underline the command word, count the marks (one mark per point expected), and answer in the format the command word demands.
This lesson is examined by: AQA 8552 | Edexcel 1DT0 | OCR J310 | Eduqas comps | CCEA units. Tier and paper details vary - always check your board's current specification.
Follow-up revision: DT6-materials-and-their-working-properties on GCSE Revise (notes, flashcards and auto-graded target tests for this exact topic).