Exothermic And Endothermic Reactions

Chemistry OCR
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C15: Exothermic and Endothermic Reactions

FoundationHigher AQAEdexcelOCRCCEA

Energy changes and reaction profiles

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πŸ“‹ Key Definitions

Exothermic reaction: A reaction that releases energy to the surroundings, causing the temperature of the surroundings to increase. Energy is transferred from the reactants to the surroundings.
Endothermic reaction: A reaction that absorbs energy from the surroundings, causing the temperature of the surroundings to decrease. Energy is transferred from the surroundings to the reactants.
Activation energy: The minimum amount of energy that particles must have to react when they collide. Shown on reaction profiles as the energy "hill" from reactants to the peak.
Bond energy: The amount of energy needed to break a particular chemical bond, or the amount released when the bond forms. Breaking bonds is endothermic; making bonds is exothermic.

Bond Energy Calculation:

Energy change = energy absorbed (breaking bonds) βˆ’ energy released (making bonds)

If the value is negative β†’ exothermic

If the value is positive β†’ endothermic

πŸ“ Exothermic vs Endothermic

FeatureExothermicEndothermic
Energy transferReleased to surroundingsAbsorbed from surroundings
Temperature changeSurroundings get warmerSurroundings get cooler
Energy of products vs reactantsProducts have less energy than reactantsProducts have more energy than reactants
Energy change valueNegative (e.g. βˆ’571 kJ/mol)Positive (e.g. +571 kJ/mol)
Everyday examplesHand warmers, self-heating cansCold packs, sports injury packs
Chemical examplesCombustion, neutralisation, oxidationThermal decomposition, photosynthesis

πŸ“ˆ Reaction Profiles

A reaction profile (energy level diagram) shows the energy of reactants and products, and the activation energy.

Reading reaction profiles:
  • Exothermic: Products are at a lower energy level than reactants. The arrow showing energy change points downwards.
  • Endothermic: Products are at a higher energy level than reactants. The arrow showing energy change points upwards.
  • Activation energy: The arrow from reactants up to the peak of the curve. Both exothermic and endothermic reactions have activation energy.
Worked Example 1: Identifying reaction type from a profile

A reaction profile shows the products at a lower energy level than the reactants. Is this exothermic or endothermic?

Since the products have less energy than the reactants, energy has been released to the surroundings.

This is an exothermic reaction.

⚑ Bond Energy Calculations

Every chemical bond has a bond energy β€” the energy required to break it. When new bonds form, energy is released. The overall energy change depends on the balance between energy needed to break bonds and energy released when new bonds form.

Steps for bond energy calculations:

1. Calculate total energy required to break all bonds in the reactants

2. Calculate total energy released when all new bonds form in the products

3. Energy change = energy in (breaking) βˆ’ energy out (making)

Worked Example 2: Bond energy calculation for Hβ‚‚ + Clβ‚‚ β†’ 2HCl

Bond energies: Hβˆ’H = 436 kJ/mol, Clβˆ’Cl = 242 kJ/mol, Hβˆ’Cl = 431 kJ/mol

Step 1: Energy to break bonds = Hβˆ’H + Clβˆ’Cl = 436 + 242 = 678 kJ/mol

Step 2: Energy released making bonds = 2 Γ— Hβˆ’Cl = 2 Γ— 431 = 862 kJ/mol

Step 3: Energy change = 678 βˆ’ 862 = βˆ’184 kJ/mol

Negative value β†’ exothermic. More energy released than absorbed.

Worked Example 3: Bond energy calculation for CHβ‚„ + 2Oβ‚‚ β†’ COβ‚‚ + 2Hβ‚‚O

Bond energies: Cβˆ’H = 413, O=O = 498, C=O = 805, Oβˆ’H = 464 (all kJ/mol)

Step 1: Energy to break bonds = (4 Γ— Cβˆ’H) + (2 Γ— O=O) = (4 Γ— 413) + (2 Γ— 498) = 1652 + 996 = 2648 kJ/mol

Step 2: Energy released making bonds = (2 Γ— C=O) + (4 Γ— Oβˆ’H) = (2 Γ— 805) + (4 Γ— 464) = 1610 + 1856 = 3466 kJ/mol

Step 3: Energy change = 2648 βˆ’ 3466 = βˆ’818 kJ/mol

Negative β†’ exothermic (combustion is always exothermic).

Worked Example 4: Endothermic bond energy calculation

For the reaction Hβ‚‚ + Iβ‚‚ β†’ 2HI, calculate the energy change.

Bond energies: Hβˆ’H = 436, Iβˆ’I = 151, Hβˆ’I = 299 (all kJ/mol)

Step 1: Energy to break bonds = 436 + 151 = 587 kJ/mol

Step 2: Energy released making bonds = 2 Γ— 299 = 598 kJ/mol

Step 3: Energy change = 587 βˆ’ 598 = βˆ’11 kJ/mol

This is slightly exothermic (very close to zero).

πŸ”₯ Common Exothermic Reactions

Worked Example 5: Exothermic reactions

Combustion: Fuel + oxygen β†’ carbon dioxide + water. E.g. CHβ‚„ + 2Oβ‚‚ β†’ COβ‚‚ + 2Hβ‚‚O. Releases lots of heat and light.

Neutralisation: Acid + alkali β†’ salt + water. E.g. HCl + NaOH β†’ NaCl + Hβ‚‚O. Temperature of the solution rises.

Oxidation: E.g. adding water to calcium oxide: CaO + Hβ‚‚O β†’ Ca(OH)β‚‚. Used in self-heating cans.

❄️ Common Endothermic Reactions

Worked Example 6: Endothermic reactions

Thermal decomposition: Heating calcium carbonate: CaCO₃ β†’ CaO + COβ‚‚. Heat must be continuously supplied.

Photosynthesis: 6COβ‚‚ + 6Hβ‚‚O β†’ C₆H₁₂O₆ + 6Oβ‚‚. Energy from sunlight is absorbed.

Sports injury packs: Ammonium nitrate dissolving in water β€” absorbs heat, making the pack feel cold.

❓ Practice Questions

Q1: Foundation Define exothermic and endothermic reactions.

Q2: Foundation Classify each of the following as exothermic or endothermic: combustion, thermal decomposition, neutralisation, photosynthesis.

Q3: Higher For the reaction Nβ‚‚ + 3Hβ‚‚ β†’ 2NH₃, calculate the energy change. Bond energies: N≑N = 945, Hβˆ’H = 436, Nβˆ’H = 391 (all kJ/mol).

Q4: Foundation Describe how the reaction profile of an exothermic reaction differs from that of an endothermic reaction.

Q5: Higher Explain, in terms of bond breaking and bond making, why combustion reactions are exothermic.

βœ… Answers

  1. Exothermic: releases energy to surroundings, temperature increases. Endothermic: absorbs energy from surroundings, temperature decreases.
  2. Combustion = exothermic. Thermal decomposition = endothermic. Neutralisation = exothermic. Photosynthesis = endothermic.
  3. Energy in (breaking): N≑N + 3(Hβˆ’H) = 945 + (3 Γ— 436) = 945 + 1308 = 2253 kJ/mol. Energy out (making): 6 Γ— Nβˆ’H (because 2NH₃ has 6 Nβˆ’H bonds) = 6 Γ— 391 = 2346 kJ/mol. Energy change = 2253 βˆ’ 2346 = βˆ’93 kJ/mol (exothermic).
  4. Exothermic: products at lower energy level than reactants, energy change arrow points down. Endothermic: products at higher energy level, energy change arrow points up. Both have activation energy (the hill from reactants to the peak).
  5. In combustion, the bonds formed in the products (C=O and Oβˆ’H) release more energy than was needed to break the bonds in the reactants (Cβˆ’H and O=O). Since more energy is released making bonds than absorbed breaking bonds, the reaction is exothermic.

πŸ”¬ Required Practical

PAG β€” Temperature Changes in Reactions

  1. Place a fixed volume of dilute acid in a polystyrene cup with a lid, and record its starting temperature
  2. Add a measured amount of the second reactant (e.g. metal powder or alkali), fit the lid with a thermometer through it, and stir gently
  3. Record the maximum (or minimum) temperature reached
  4. Calculate the temperature change (Ξ”T = final βˆ’ initial): a rise is exothermic, a fall is endothermic
  5. Repeat with different concentrations to investigate the effect on Ξ”T
  6. Variables: concentration (independent), maximum temperature change (dependent), volumes and starting temperatures (controls)
Common errors: heat loss without the lid and polystyrene cup; recording the temperature too late (the maximum passes quickly); unequal starting temperatures between trials

🧭 Board Focus β€” OCR

Spec J248 (Gateway). Two written papers with Foundation/Higher tiers, organised into chapters C1–C8 covering particles, reactions, quantitative chemistry, electrolysis, organic and analysis. The chapter split between the two papers differs by tier β€” check the current paper structure for your entry. Practical skills (PAGs) are examined within the written papers.

Always check: specification details change β€” confirm paper structure and set texts against the current specification for your exam year.

🎯 Exam Tips

πŸ”’ Maths Skills

Mathematical Skills

Bond energy calculations: 1) Calculate total energy to break all bonds in reactants (energy in). 2) Calculate total energy released making all bonds in products (energy out). 3) Energy change = energy in βˆ’ energy out. Negative = exothermic; positive = endothermic.

Example: Hβ‚‚ + Clβ‚‚ β†’ 2HCl. Energy in = 436 + 242 = 678 kJ/mol. Energy out = 2 Γ— 431 = 862 kJ/mol. Ξ”H = 678 βˆ’ 862 = βˆ’184 kJ/mol (exothermic).

⚠️ Common Misconceptions

Watch Out!

Breaking bonds releases energy. Wrong: breaking bonds releases energy Correct: breaking bonds requires energy (endothermic); making bonds releases energy (exothermic)

Exothermic reactions are always fast. Wrong: exothermic reactions are always fast Correct: the speed of a reaction (rate) is independent of the energy change β€” an exothermic reaction can be slow (e.g. rusting) and an endothermic reaction can be fast

✍️ 6-Mark Question

Extended Answer

6 marks: Explain exothermic and endothermic reactions using bond energies.

In a chemical reaction, bonds in the reactants must first be broken, which requires energy (endothermic). New bonds then form in the products, which releases energy (exothermic). If the energy released when new bonds form is greater than the energy needed to break the original bonds, the reaction is exothermic β€” more energy is given out than taken in, so the surroundings get warmer and Ξ”H is negative. If the energy needed to break bonds is greater than the energy released making new bonds, the reaction is endothermic β€” more energy is taken in than given out, the surroundings get cooler and Ξ”H is positive. For example, combustion is exothermic because the C=O and Oβˆ’H bonds formed in COβ‚‚ and Hβ‚‚O release more energy than was needed to break the Cβˆ’H and O=O bonds in the reactants.

Mark scheme: 1 mark for bond breaking requires energy; 1 mark for bond making releases energy; 1 mark for exothermic = more energy released than absorbed; 1 mark for endothermic = more energy absorbed than released; 1 mark for correct sign of Ξ”H; 1 mark for combustion example.

πŸ“Š AO3: Analyse & Evaluate

Analysis and Evaluation

A student investigates the reaction between hydrogen and chlorine: Hβ‚‚ + Clβ‚‚ β†’ 2HCl. Bond energies: Hβˆ’H = 436, Clβˆ’Cl = 242, Hβˆ’Cl = 431 kJ/mol.

Question: Calculate the enthalpy change. Is the reaction exothermic or endothermic? A student says "the Hβˆ’Cl bond is weaker than the Hβˆ’H bond so the reaction must be endothermic." Evaluate this statement.

Answer: Energy in = 436 + 242 = 678 kJ/mol. Energy out = 2 Γ— 431 = 862 kJ/mol. Ξ”H = 678 βˆ’ 862 = βˆ’184 kJ/mol (exothermic). The student's statement is incorrect because the overall energy change depends on ALL bonds broken and formed, not just one comparison. Although Hβˆ’Cl is weaker than Hβˆ’H, two Hβˆ’Cl bonds are formed per molecule, and the Clβˆ’Cl bond is much weaker than Hβˆ’H, so the total energy released making bonds exceeds the total energy needed to break bonds.

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