B12: Photosynthesis
The process of photosynthesis, factors affecting rate, uses of glucose
The process of photosynthesis, factors affecting rate, uses of glucose
A student writes: "Plants make oxygen by photosynthesis." Improve this statement.
Solution:
Oxygen is a by-product. The main product is glucose. A better statement is: "Plants use light energy to convert carbon dioxide and water into glucose. Oxygen is produced as a by-product."
| Factor | Effect on Rate | How It Works |
|---|---|---|
| Light intensity | Increasing light increases rate (up to a plateau) | More light = more energy absorbed by chlorophyll. Eventually another factor becomes limiting. |
| CO₂ concentration | Increasing CO₂ increases rate (up to a plateau) | More CO₂ = more raw material for the reaction. Eventually another factor becomes limiting. |
| Temperature | Rate increases to an optimum, then decreases | Higher temperature = more kinetic energy = faster enzyme action. Above ~45°C, enzymes denature and rate falls sharply. |
A plant is grown at high light intensity but low CO₂. What is the limiting factor and how could you increase the rate of photosynthesis?
Solution:
CO₂ concentration is the limiting factor because it is in shortest supply.
To increase the rate, increase the CO₂ concentration (e.g. by growing in a greenhouse with enriched CO₂ air).
At 20°C, increasing light intensity increases the rate of photosynthesis. At 35°C, increasing light intensity has no effect. Explain why.
Solution:
At 20°C, light is the limiting factor, so increasing light increases the rate.
At 35°C, temperature is now the limiting factor (enzymes are working at their maximum but not yet denatured). Increasing light does not help because the enzymes cannot work any faster at this temperature.
A lamp is 10 cm from some pondweed. The lamp is moved to 20 cm away. What happens to the light intensity?
Solution:
Distance has doubled from 10 cm to 20 cm.
Light intensity = 1/d², so new intensity = 1/20² = 1/400
Original intensity = 1/10² = 1/100
New intensity = (1/400) ÷ (1/100) = 100/400 = ¼ of original
The light intensity is reduced to one quarter.
A lamp is 5 cm from a plant. It is moved to 15 cm away. Calculate the factor by which light intensity changes.
Solution:
Distance has tripled from 5 cm to 15 cm.
New intensity = 1/15² = 1/225
Original intensity = 1/5² = 1/25
Factor = (1/225) ÷ (1/25) = 25/225 = 1/9
Light intensity is reduced to one ninth of the original.
| Use of Glucose | Details |
|---|---|
| Respiration | Glucose is broken down to release energy for cellular processes (transferred to all cells) |
| Starch (storage) | Glucose is converted to starch (insoluble) for storage in roots, stems and leaves. Starch does not affect water potential. |
| Cellulose (cell walls) | Glucose is converted to cellulose for making strong cell walls, especially in fast-growing plants |
| Lipids (fats/oils) | Glucose is converted to lipids for energy storage, particularly in seeds |
| Amino acids (with nitrates) | Glucose is combined with nitrate ions (absorbed from soil) to make amino acids, which are built into proteins |
A plant is growing in soil that is deficient in nitrates. Explain why the plant may show poor growth even though it is photosynthesising normally.
Solution:
Without nitrates, the plant cannot convert glucose into amino acids.
Without amino acids, the plant cannot make proteins needed for growth (e.g. enzymes, structural proteins).
Therefore growth is limited despite sufficient glucose from photosynthesis.
Explain why plants convert glucose to starch for storage rather than storing glucose itself.
Solution:
Glucose is soluble in water. If stored as glucose, it would dissolve and affect the water potential of the cell, drawing water in by osmosis and potentially causing the cell to burst.
Starch is insoluble, so it does not affect the water potential and can be stored safely in large amounts without affecting osmosis.
In a photosynthesis experiment, a student counts bubbles at distances of 5 cm, 10 cm, 15 cm and 20 cm from a lamp. The results are 120, 32, 14 and 8 bubbles per minute. Explain the pattern.
Solution:
As distance increases, light intensity decreases (inverse square law: light intensity ∝ 1/d²).
At 5 cm: high light intensity → fast photosynthesis → 120 bubbles/min
At 10 cm: light intensity is ¼ of 5 cm value → 32 bubbles/min (roughly ¼ of 120)
At 15 cm and 20 cm: light intensity is very low, so light is still the limiting factor and rate continues to drop.
The pattern approximately follows the inverse square law.
Q1: Write the word equation and symbol equation for photosynthesis.
Q2: Name the three limiting factors for photosynthesis and explain how each affects the rate.
Q3: Higher A lamp is moved from 10 cm to 30 cm away from a plant. By what factor does the light intensity change?
Q4: State three ways plants use the glucose produced by photosynthesis.
Q5: Explain why a plant converts glucose to starch for storage rather than storing glucose directly.
Q6: Describe how you would investigate the effect of light intensity on the rate of photosynthesis using pondweed, including the variables you would control.
Cut a piece of pondweed (Cabomba or Elodea) and place it upside down in a beaker of water with sodium hydrogencarbonate (provides CO₂). Place a lamp at a measured distance and count the oxygen bubbles produced per minute. Repeat at different distances. For greater accuracy, use an oxygen sensor connected to a data logger instead of counting bubbles. Control variables: temperature (use a water bath), CO₂ concentration (same NaHCO₃), same length and species of pondweed. Independent variable: distance of lamp. Dependent variable: number of bubbles per minute or oxygen concentration.
Inverse square law: Light intensity is inversely proportional to the square of the distance: light intensity ∝ 1/d². If the distance doubles, the light intensity falls to ¼. If the distance triples, the light intensity falls to 1/9. Calculate using: new intensity = original intensity × (original distance / new distance)².
1. Plants only respire at night. Wrong: plants respire only in the dark. Correct: plants respire continuously, day and night — respiration happens in all living cells all the time.
2. More CO₂ always means more photosynthesis. Wrong: increasing CO₂ will always increase the rate. Correct: other factors (light intensity, temperature) can become limiting, so increasing CO₂ beyond a certain point has no further effect.
6 marks: Explain how light intensity affects the rate of photosynthesis.
As light intensity increases, the rate of photosynthesis increases because more light energy is absorbed by chlorophyll, providing more energy for the reaction. The rate increases proportionally at low light intensities where light is the limiting factor. However, at higher light intensities the rate plateaus because another factor (such as CO₂ concentration or temperature) becomes the limiting factor. The relationship between light intensity and distance follows the inverse square law: light intensity ∝ 1/d², so doubling the distance reduces the light intensity to one quarter, causing a significant drop in the rate of photosynthesis.
Mark scheme: 1 mark — light increases rate; 1 mark — more energy absorbed by chlorophyll; 1 mark — proportional increase at low intensity; 1 mark — plateau when another factor limits; 1 mark — inverse square law; 1 mark — correct use of 1/d² relationship.
A student measured the volume of oxygen gas collected from pondweed at different light intensities. At light intensities of 5, 10, 20 and 40 arbitrary units, the oxygen collected in 5 minutes was 2 cm³, 4 cm³, 7 cm³ and 7.5 cm³ respectively. Explain the pattern in the results and suggest why the increase in oxygen volume becomes smaller at higher light intensities. Identify the limiting factor at 40 arbitrary units of light and suggest how you could test your answer.
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