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E3: Capacitors & Inductors

WJEC Eduqas C690QS

Capacitance, charge storage, RC circuits, inductance and energy storage

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Capacitors & Inductors

Capacitance, charge storage, RC circuits, inductance and energy storage

Key Fact: Capacitance C = Q/V, measured in farads (F); a capacitor stores charge on parallel plates separated by a dielectric.
Key Fact: The energy stored in a capacitor is E = ½CV² = ½QV.
Key Fact: In an RC charging circuit, V_C rises exponentially: V_C = V_supply(1 − e^(−t/RC)).
Key Fact: The time constant τ = RC is the time for the capacitor to reach 63.2% of its final voltage when charging.
Key Fact: During discharge, V_C = V_initial × e^(−t/RC); after 5τ the capacitor is effectively fully discharged.
Key Fact: Inductance L is measured in henrys (H); an inductor stores energy in its magnetic field.
Key Fact: The energy stored in an inductor is E = ½LI².
Key Fact: An inductor opposes changes in current: V = L × dI/dt (back EMF).
Key Fact: Capacitors block DC at steady state but pass AC; inductors pass DC at steady state but oppose AC.
Key Fact: Dielectric material between capacitor plates increases capacitance by reducing the electric field.
Key Fact: Increasing plate area or decreasing plate separation increases capacitance.
Key Fact: Inductors in series add: L_total = L1 + L2; in parallel: 1/L_total = 1/L1 + 1/L2.

📋 Key Vocabulary and Concepts

For Capacitors & Inductors, you must know:

❓ Practice Questions

Q: A 100 μF capacitor is charged to 10 V. How much charge is stored?

Q: What is the time constant of a circuit with R = 10 kΩ and C = 20 μF?

Q: How much energy is stored in a 47 μF capacitor charged to 12 V?

Q: What is the energy stored in a 10 mH inductor carrying 2 A?

Q: After how many time constants is a discharging capacitor considered fully discharged?

✅ Answers

  1. Q = CV = 100 × 10⁻⁶ × 10 = 1 × 10⁻³ C = 1 mC.
  2. τ = RC = 10 × 10³ × 20 × 10⁻⁶ = 0.2 s.
  3. E = ½CV² = 0.5 × 47 × 10⁻⁶ × 144 = 3.384 × 10⁻³ J ≈ 3.4 mJ.
  4. E = ½LI² = 0.5 × 10 × 10⁻³ × 4 = 20 × 10⁻³ J = 20 mJ.
  5. After 5τ, the capacitor voltage has fallen to less than 1% of its initial value and is considered fully discharged.

🎯 Exam Tips

📝 Exam Technique

GCSE Electronics Exam Tips — Capacitors & Inductors:
1. For Capacitors & Inductors questions, use correct electronic symbols and terminology
2. Always show your working in calculations, including units at each step
3. When analysing circuits, state which law or rule you are applying first
4. For evaluation questions on Capacitors & Inductors, compare component choices and consider cost, reliability and tolerance
5. Draw circuit diagrams neatly with conventional symbols

⚠️ Common Errors

✗ Forgetting to convert μF or mF to farads before calculation. ✓ Always convert: 100 μF = 100 × 10⁻⁶ F.

✗ Using E = CV² instead of E = ½CV² for capacitor energy. ✓ The correct formula is E = ½CV², which includes the factor of ½.

✗ Saying a capacitor is fully charged after one time constant. ✓ After one time constant (τ), the capacitor has reached only 63.2% of its final voltage.

✗ Confusing capacitor and inductor behaviour with DC at steady state. ✓ A capacitor blocks DC at steady state; an inductor acts as a short circuit to DC at steady state.

✍️ Model Answer

Full-Mark Response

Describe how a capacitor charges and discharges in an RC circuit, explaining the significance of the time constant.

When a capacitor charges through a resistor from a supply voltage V_s, the voltage across the capacitor rises exponentially: V_C = V_s(1 − e^(−t/RC)). The current starts at its maximum value I = V_s/R and decays exponentially. The time constant τ = RC is the time taken for the capacitor voltage to reach 63.2% of V_s. After 5τ the capacitor is effectively fully charged (~99.3%). During discharge, V_C = V_0 × e^(−t/RC), where V_0 is the initial voltage. The voltage falls to 36.8% of V_0 after one time constant and is effectively zero after 5τ. A larger R or C gives a larger time constant, meaning slower charging and discharging. The exponential behaviour occurs because the charging rate depends on the remaining voltage difference, which decreases as the capacitor charges.

📊 AO Deep Dive

Assessment Objective Analysis

AO1 (Knowledge & Understanding): Demonstrate knowledge and understanding of capacitors & inductors, including electronic components, circuit theory and systems concepts relevant to WJEC Eduqas C690QS.

AO2 (Application): Apply knowledge and understanding of capacitors & inductors to analyse, design and construct electronic circuits and systems.

AO3 (Evaluation): Evaluate electronic circuits and systems, making reasoned judgements about design choices, performance and practical considerations, constructing supported arguments.

📝 Exam Questions by Topic

🎬 Video Resources

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