G6: Geometric Proof
Apply angle facts, triangle congruence, similarity and properties of quadrilaterals to conjecture and derive results
Apply angle facts, triangle congruence, similarity and properties of quadrilaterals to conjecture and derive results
Prove that the base angles of an isosceles triangle are equal.
Proof:
Given: Triangle ABC with AB = AC
Construction: Draw the angle bisector of angle A, meeting BC at D
In triangles ABD and ACD:
Therefore triangles ABD and ACD are congruent (SAS)
Therefore Angle B = Angle C (corresponding angles in congruent triangles)
Prove that opposite sides of a parallelogram are equal.
Proof:
Given: Parallelogram ABCD with AB ∥ DC and AD ∥ BC
Draw diagonal AC
In triangles ABC and CDA:
Therefore triangles ABC and CDA are congruent (ASA)
Therefore AB = CD and BC = AD (corresponding sides in congruent triangles)
Prove that the angle at the centre is twice the angle at the circumference subtended by the same arc.
Proof:
Given: Points A, B, C on a circle, with O at the centre
Case: When one side of the angle at the circumference passes through the centre
Join OA and OB
OA = OB (radii), so triangle OAB is isosceles
Let angle OAB = angle OBA = x
Angle AOB = 180° - 2x
Angle at circumference = x
Angle at centre = 180° - 2x = 2(90° - x)
Using similar reasoning for other cases, the angle at the centre = 2 × angle at circumference
Prove that the line joining the midpoints of two sides of a triangle is parallel to the third side and half its length.
Proof:
Given: Triangle ABC, D and E are midpoints of AB and AC
In triangles ADE and ABC:
Therefore triangles ADE and ABC are similar (AAA)
Since D and E are midpoints, AD/AB = AE/AC = 1/2
Scale factor = 1/2, so DE = (1/2)BC
DE ∥ BC (corresponding angles are equal)
Q1: What are the four criteria for congruent triangles?
Q2: Prove that the diagonals of a parallelogram bisect each other.
Q3: Prove that vertically opposite angles are equal.
Q4: What does AAA prove instead of congruence?
Q5: State the key steps in writing a geometric proof.
Prove that the angle sum of a quadrilateral is 360° by splitting it into two triangles.
Solution: Draw diagonal AC in quadrilateral ABCD. This creates two triangles: ABC and ACD. The angle sum of △ABC = 180° (angles in a triangle). The angle sum of △ACD = 180°. The angles of both triangles together = 360°. The angles of the two triangles make up all four angles of the quadrilateral. Therefore, the angle sum of ABCD = 360°.
1. Wrong: Making a statement without giving a reason (e.g. "∠A = ∠C because they look equal") Correct: Every statement must have a geometric reason, e.g. "∠A = ∠C (base angles of an isosceles triangle)" or "(alternate angles, AB ∥ CD)".
2. Wrong: Using circular reasoning — assuming what you need to prove Correct: Never use the conclusion as a step in the proof. Start only from given facts and known theorems.
3. Wrong: Proving similarity when the question asks for congruence (or vice versa) Correct: Congruence means identical shape AND size. Similarity means same shape but possibly different sizes. Read the question carefully.
6 marks: ABCD is a parallelogram. E is the midpoint of AB and F is the midpoint of DC. Prove that (a) △ADE ≡ △BCF, and (b) DE is parallel to BF.
(a) In parallelogram ABCD: AD = BC (opposite sides of parallelogram), ∠DAE = ∠BCF (opposite angles of parallelogram), AE = EB and DF = FC (midpoints), so AE = FC (each is half of AB = half of DC since AB = DC). Therefore △ADE ≡ △BCF by SAS.
(b) Since △ADE ≡ △BCF, ∠ADE = ∠CBF (corresponding angles in congruent triangles). Since ∠ADE and ∠CBF are alternate angles formed by transversal DB crossing DE and BF, and they are equal, DE is parallel to BF (alternate angles equal → lines parallel).
Mark scheme: M1 identifying equal sides/angles, A1 parallelogram properties stated, M1 SAS congruence, A1 proven, M1 corresponding angles, A1 parallel lines conclusion
A student tries to prove that the base angles of an isosceles triangle are equal by drawing the triangle and measuring the angles.
(a) Why is measurement not a valid method of proof?
(b) Outline a proper geometric proof that the base angles of an isosceles triangle are equal.
(c) Another student says "I've shown it works for three different isosceles triangles, so it must be true for all." What is wrong with this argument?
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