A8: Coordinates
Work with coordinates in all four quadrants
Work with coordinates in all four quadrants
| Quadrant | x | y | Examples |
|---|---|---|---|
| 1st (top right) | + | + | (3, 4), (7, 2) |
| 2nd (top left) | - | + | (-3, 4), (-5, 1) |
| 3rd (bottom left) | - | - | (-2, -5), (-4, -3) |
| 4th (bottom right) | + | - | (3, -2), (6, -4) |
Identify the quadrant for each point:
a) (5, 3) โ 1st quadrant (both positive)
b) (-2, 4) โ 2nd quadrant (x negative, y positive)
c) (-3, -1) โ 3rd quadrant (both negative)
d) (4, -2) โ 4th quadrant (x positive, y negative)
Plot the points A(2, 3), B(-1, 4), C(-2, -3), D(3, -2)
Method:
A(2, 3): Start at origin, go 2 right, 3 up
B(-1, 4): Start at origin, go 1 left, 4 up
C(-2, -3): Start at origin, go 2 left, 3 down
D(3, -2): Start at origin, go 3 right, 2 down
Find the midpoint of A(2, 4) and B(6, 8)
Solution:
Midpoint = (2 + 6โ2, 4 + 8โ2)
= (8โ2, 12โ2)
= (4, 6)
Find the midpoint of P(-3, 2) and Q(5, -4)
Solution:
Midpoint = (-3 + 5โ2, 2 + (-4)โ2)
= (2โ2, -2โ2)
= (1, -1)
Find the coordinates of the point on the y-axis that is the same distance from A(2, 5) and B(2, -3).
Solution:
Points on the y-axis have x = 0, so we're looking for (0, y).
Since A and B have the same x-coordinate (2), the midpoint lies on the y-axis.
Midpoint y = 5 + (-3)โ2 = 2โ2 = 1
Answer: (0, 1)
Find the distance between A(2, 3) and B(7, 3)
Solution:
Since y-values are equal, distance = |7 - 2| = 5
Find the distance between P(-2, 1) and Q(-2, -4)
Solution:
Since x-values are equal, distance = |1 - (-4)| = |1 + 4| = 5
Coordinates: x first (across), y second (up). Midpoint = average the xโs, average the yโs.
Find the midpoint of (2, โ3) and (8, 5).
x: (2 + 8) รท 2 = 5 ยท y: (โ3 + 5) รท 2 = 1
Midpoint: (5, 1)
M1 for averaging, A1 for (5, 1). Works with negatives: the average of โ3 and 5 is +1.
Write down the coordinates of the point 4 units LEFT and 2 units DOWN from (1, 6).
Left = x decreases: 1 โ 4 = โ3. Down = y decreases: 6 โ 2 = 4
(โ3, 4)
B1 for (โ3, 4). Left/right change x; up/down change y โ never both.
Exam wording to expect: "Write down the coordinates of โฆ", "Find the midpoint of A and B", "Plot the point โฆ".
Q1: In which quadrant is the point (-4, 3)?
Q2: What are the coordinates of a point 3 units right of (-2, 5)?
Q3: Find the midpoint of (4, 2) and (10, 8).
Q4: Find the midpoint of (-2, 3) and (6, -5).
Q5: Point A is (3, -2). Point B is on the x-axis, directly below A. What are the coordinates of B?
Q6: What is the distance between (-3, 5) and (-3, -1)?
Q7: Find the midpoint of (โ4, 7) and (2, โ1)
Q8: A square has vertices (1,1), (5,1) and (5,5). Write the fourth vertex.
Every mark comes from the working, not just the answer. These model answers show the lines a mark scheme expects to see.
Q1. Negative x, positive y โ 2nd quadrant
Q2. 3 right from (โ2, 5): โ2 + 3 โ (1, 5)
Q3. x: (4 + 10)/2 = 7; y: (2 + 8)/2 = 5 โ (7, 5)
Q4. x: (โ2 + 6)/2 = 2; y: (3 + (โ5))/2 = โ1 โ (2, โ1)
Q5. Directly below on the x-axis โ same x, y = 0 โ (3, 0)
Q6. Same x (vertical line): 5 โ (โ1) = 6 units
Q7. x: (โ4 + 2)/2 = โ1; y: (7 + (โ1))/2 = 3 โ (โ1, 3)
Q8. Missing corner completes the square: (1, 5)
Coordinates feed straight-line graphs, transformations and Pythagoras distance: 1โ3 marks each time. Midpoint and quadrant recall are Paper 1 regulars.
Links to: straight-line graphs (A9/A10), transformations (G7), Pythagoras (G20).
Cover the answers, work each one, then mark yourself. If any takes over a minute, revisit the matching section above.
Spec 8300. Three papers, each 80 marks and 1h30: Paper 1 non-calculator, Papers 2 and 3 calculator. Foundation/Higher tiers. Roughly a third of the marks sit under AO2 (reasoning) and AO3 (problem-solving), so show every line of working โ method marks survive arithmetic slips.
Always check: specification details change โ confirm paper structure and set texts against the current specification for your exam year.
Three vertices of a parallelogram are A(1, 2), B(5, 2) and D(3, 6). Find the coordinates of vertex C.
Solution:
Step 1: Midpoint of diagonal BD = (5+3โ2, 2+6โ2) = (4, 4)
Step 2: Diagonals of a parallelogram bisect each other, so midpoint of AC = (4, 4)
Step 3: (1+xโ2, 2+yโ2) = (4, 4), so 1+x = 8 and 2+y = 8, giving C = (7, 6)
1. Wrong: Writing coordinates as (y, x) Correct: Always (x, y) โ x comes first
2. Wrong: (-2, 5) is in the 4th quadrant Correct: (-2, 5) is in the 2nd quadrant (x negative, y positive)
3. Wrong: Midpoint formula adds coordinates and doesn't divide by 2 Correct: Midpoint = average of x-values, average of y-values โ must divide by 2
6 marks: A(2, 3) and B(8, 7) are opposite vertices of a rectangle with sides parallel to the axes. (a) Find the other two vertices C and D. (b) Find the midpoint of the diagonal AB. (c) Find the area of the rectangle.
(a) The other vertices must share x and y coordinates with A and B: C = (8, 3) and D = (2, 7)
(b) Midpoint = (2+8โ2, 3+7โ2) = (5, 5)
(c) Length = |8 - 2| = 6, Width = |7 - 3| = 4. Area = 6 ร 4 = 24 square units
Mark scheme: (a) 2 marks for both vertices. (b) 2 marks. (c) 2 marks for length, width and area.
A phone mast at point M has signal covering all points within 5 km. Town A is at (2, 4) and Town B at (8, 4) on a map where 1 unit = 1 km.
(a) If M is at (5, 4), does Town A get signal?
(b) Does Town B get signal?
(c) Where should M be placed so both towns just get signal?
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