GCSE Revision Aid: This resource is designed to support your revision and may contain errors. If you find a discrepancy with your class teaching, your teacher is correct โ€” please let us know at gcserevise@scott.scottrix.co.uk.

A8: Coordinates

Foundation Higher AQAEdexcelOCREduqasCCEA

Work with coordinates in all four quadrants

Fastmail

๐Ÿ“‹ Key Concepts

Coordinates: Pairs of numbers (x, y) that specify a position on a grid. The x-coordinate comes first, then y.
Format: (x, y)
x = horizontal position (left/right)
y = vertical position (up/down)
Remember: "Along the corridor, up the stairs" - x first, then y.

๐Ÿ“ The Four Quadrants

Quadrants: The coordinate grid is divided into four sections:
QuadrantxyExamples
1st (top right)++(3, 4), (7, 2)
2nd (top left)-+(-3, 4), (-5, 1)
3rd (bottom left)--(-2, -5), (-4, -3)
4th (bottom right)+-(3, -2), (6, -4)
Example 1

Identify the quadrant for each point:

a) (5, 3) โ†’ 1st quadrant (both positive)

b) (-2, 4) โ†’ 2nd quadrant (x negative, y positive)

c) (-3, -1) โ†’ 3rd quadrant (both negative)

d) (4, -2) โ†’ 4th quadrant (x positive, y negative)

๐Ÿ“ Plotting Coordinates

Example 2

Plot the points A(2, 3), B(-1, 4), C(-2, -3), D(3, -2)

Method:

A(2, 3): Start at origin, go 2 right, 3 up

B(-1, 4): Start at origin, go 1 left, 4 up

C(-2, -3): Start at origin, go 2 left, 3 down

D(3, -2): Start at origin, go 3 right, 2 down

๐Ÿ“ Finding Midpoints

Midpoint formula: The midpoint M of two points (xโ‚, yโ‚) and (xโ‚‚, yโ‚‚) is:
M = (xโ‚ + xโ‚‚โ„2, yโ‚ + yโ‚‚โ„2)
Example 3

Find the midpoint of A(2, 4) and B(6, 8)

Solution:

Midpoint = (2 + 6โ„2, 4 + 8โ„2)

= (8โ„2, 12โ„2)

= (4, 6)

Example 4

Find the midpoint of P(-3, 2) and Q(5, -4)

Solution:

Midpoint = (-3 + 5โ„2, 2 + (-4)โ„2)

= (2โ„2, -2โ„2)

= (1, -1)

๐Ÿ“ Special Lines

Key facts:
  • x-axis: All points have y = 0, e.g., (3, 0), (-2, 0)
  • y-axis: All points have x = 0, e.g., (0, 4), (0, -3)
  • Origin: The point (0, 0) where axes meet
  • Vertical line x = a: All points where x = a
  • Horizontal line y = b: All points where y = b
Example 5

Find the coordinates of the point on the y-axis that is the same distance from A(2, 5) and B(2, -3).

Solution:

Points on the y-axis have x = 0, so we're looking for (0, y).

Since A and B have the same x-coordinate (2), the midpoint lies on the y-axis.

Midpoint y = 5 + (-3)โ„2 = 2โ„2 = 1

Answer: (0, 1)

๐Ÿ“ Distance Between Points

Horizontal distance: |xโ‚‚ - xโ‚| (ignore y values)
Vertical distance: |yโ‚‚ - yโ‚| (ignore x values)
Example 6

Find the distance between A(2, 3) and B(7, 3)

Solution:

Since y-values are equal, distance = |7 - 2| = 5

Example 7

Find the distance between P(-2, 1) and Q(-2, -4)

Solution:

Since x-values are equal, distance = |1 - (-4)| = |1 + 4| = 5

๐Ÿงฎ Worked Examples โ€” Exam Style

Coordinates: x first (across), y second (up). Midpoint = average the xโ€™s, average the yโ€™s.

Find the midpoint of (2, โˆ’3) and (8, 5).

x: (2 + 8) รท 2 = 5  ยท  y: (โˆ’3 + 5) รท 2 = 1

Midpoint: (5, 1)

M1 for averaging, A1 for (5, 1). Works with negatives: the average of โˆ’3 and 5 is +1.

Write down the coordinates of the point 4 units LEFT and 2 units DOWN from (1, 6).

Left = x decreases: 1 โˆ’ 4 = โˆ’3. Down = y decreases: 6 โˆ’ 2 = 4

(โˆ’3, 4)

B1 for (โˆ’3, 4). Left/right change x; up/down change y โ€” never both.

Exam wording to expect: "Write down the coordinates of โ€ฆ", "Find the midpoint of A and B", "Plot the point โ€ฆ".

โ“ Practice Questions

Q1: In which quadrant is the point (-4, 3)?

Q2: What are the coordinates of a point 3 units right of (-2, 5)?

Q3: Find the midpoint of (4, 2) and (10, 8).

Q4: Find the midpoint of (-2, 3) and (6, -5).

Q5: Point A is (3, -2). Point B is on the x-axis, directly below A. What are the coordinates of B?

Q6: What is the distance between (-3, 5) and (-3, -1)?

Q7: Find the midpoint of (โˆ’4, 7) and (2, โˆ’1)

Q8: A square has vertices (1,1), (5,1) and (5,5). Write the fourth vertex.

โœ… Answers

  1. 2nd quadrant
  2. (1, 5)
  3. (7, 5)
  4. (2, -1)
  5. (3, 0)
  6. 6 units

๐Ÿ“‹ Model Answers โ€” Full Working

Every mark comes from the working, not just the answer. These model answers show the lines a mark scheme expects to see.

Q1. Negative x, positive y โ†’ 2nd quadrant

Q2. 3 right from (โˆ’2, 5): โˆ’2 + 3 โ†’ (1, 5)

Q3. x: (4 + 10)/2 = 7; y: (2 + 8)/2 = 5 โ†’ (7, 5)

Q4. x: (โˆ’2 + 6)/2 = 2; y: (3 + (โˆ’5))/2 = โˆ’1 โ†’ (2, โˆ’1)

Q5. Directly below on the x-axis โ†’ same x, y = 0 โ†’ (3, 0)

Q6. Same x (vertical line): 5 โˆ’ (โˆ’1) = 6 units

Q7. x: (โˆ’4 + 2)/2 = โˆ’1; y: (7 + (โˆ’1))/2 = 3 โ†’ (โˆ’1, 3)

Q8. Missing corner completes the square: (1, 5)

๐Ÿ“Œ Key Facts to Memorise

๐Ÿ—บ๏ธ In the Exam

Coordinates feed straight-line graphs, transformations and Pythagoras distance: 1โ€“3 marks each time. Midpoint and quadrant recall are Paper 1 regulars.

Links to: straight-line graphs (A9/A10), transformations (G7), Pythagoras (G20).

โšก Targeted Drills

Cover the answers, work each one, then mark yourself. If any takes over a minute, revisit the matching section above.

๐Ÿงญ Board Focus โ€” AQA

Spec 8300. Three papers, each 80 marks and 1h30: Paper 1 non-calculator, Papers 2 and 3 calculator. Foundation/Higher tiers. Roughly a third of the marks sit under AO2 (reasoning) and AO3 (problem-solving), so show every line of working โ€” method marks survive arithmetic slips.

Always check: specification details change โ€” confirm paper structure and set texts against the current specification for your exam year.

๐ŸŽฏ Exam Tips

๐Ÿง  Problem-Solving Strategies

Problem-Solving

Use the midpoint formula to find centre points, and the distance formula (or Pythagoras) for distances. For problems involving axes, remember points on the x-axis have y = 0, and points on the y-axis have x = 0.
Multi-Step Problem

Three vertices of a parallelogram are A(1, 2), B(5, 2) and D(3, 6). Find the coordinates of vertex C.

Solution:

Step 1: Midpoint of diagonal BD = (5+3โ„2, 2+6โ„2) = (4, 4)

Step 2: Diagonals of a parallelogram bisect each other, so midpoint of AC = (4, 4)

Step 3: (1+xโ„2, 2+yโ„2) = (4, 4), so 1+x = 8 and 2+y = 8, giving C = (7, 6)

โš ๏ธ Common Errors

Watch Out!

1. Wrong: Writing coordinates as (y, x) Correct: Always (x, y) โ€” x comes first

2. Wrong: (-2, 5) is in the 4th quadrant Correct: (-2, 5) is in the 2nd quadrant (x negative, y positive)

3. Wrong: Midpoint formula adds coordinates and doesn't divide by 2 Correct: Midpoint = average of x-values, average of y-values โ€” must divide by 2

โœ๏ธ 6-Mark Exam Question

Extended Answer

6 marks: A(2, 3) and B(8, 7) are opposite vertices of a rectangle with sides parallel to the axes. (a) Find the other two vertices C and D. (b) Find the midpoint of the diagonal AB. (c) Find the area of the rectangle.

(a) The other vertices must share x and y coordinates with A and B: C = (8, 3) and D = (2, 7)

(b) Midpoint = (2+8โ„2, 3+7โ„2) = (5, 5)

(c) Length = |8 - 2| = 6, Width = |7 - 3| = 4. Area = 6 ร— 4 = 24 square units

Mark scheme: (a) 2 marks for both vertices. (b) 2 marks. (c) 2 marks for length, width and area.

๐Ÿ“Š AO3: Reason & Interpret

Reasoning and Interpretation

A phone mast at point M has signal covering all points within 5 km. Town A is at (2, 4) and Town B at (8, 4) on a map where 1 unit = 1 km.

(a) If M is at (5, 4), does Town A get signal?

(b) Does Town B get signal?

(c) Where should M be placed so both towns just get signal?

Answers: (a) Distance = |5 - 2| = 3 km < 5 km, so yes. (b) Distance = |8 - 5| = 3 km < 5 km, so yes. (c) Midpoint of A and B = (5, 4). Distance to each = 3 km < 5, so (5, 4) already works โ€” but "just" getting signal means on the edge. Actually no single point gives both towns exactly 5 km since they're only 6 km apart. Placing M at (5, 4) gives both 3 km โ€” well within range.

๐Ÿ“ Exam Questions by Topic

๐ŸŽฌ Video Resources

Share this page

Ready to ace your GCSE Mathematics exams?

Get the best revision books and guides to boost your grades.

๐Ÿง  Flashcards (Spaced Repetition)

๐Ÿ“ Exam Questions by Topic

๐ŸŽฏ Target Tests (Auto-Graded)

๐ŸŽ“ Smart Lesson (Guided)