S5: Describing Populations
Apply statistics to describe a population
Apply statistics to describe a population
| Measure | What It Tells Us |
|---|---|
| Mean | The typical average value |
| Median | The middle value (less affected by outliers) |
| Mode | The most common value |
| Range | How spread out the data is |
| IQR (Higher) | Spread of middle 50% |
A survey of 50 households found:
Write a summary of this data.
Solution:
"The average household has approximately 3 occupants. The median of 3 suggests that half of households have 3 or more people. The range of 7 indicates considerable variation in household size, from 1 to 8 occupants."
Test scores have mean = 62, median = 68. What does this tell us about the distribution?
Solution:
Mean (62) < Median (68)
The distribution is skewed left (negative skew).
A few very low scores pull the mean down, but most students scored around 68 or higher.
House prices have mean = ยฃ350,000 and median = ยฃ280,000. Describe the distribution.
Solution:
Mean > Median indicates right skew (positive skew).
A few expensive houses pull the mean up above the median.
Most houses are priced around ยฃ280,000, with some much more expensive properties.
A random sample of 200 adults found mean height = 171 cm, range = 42 cm. What can we infer about the population?
Solution:
"We can infer that the average adult height is approximately 171 cm. Heights vary considerably with a range of 42 cm. However, this is based on a sample, so the true population mean may differ slightly. A larger sample would give more reliable estimates."
Salaries at a company: ยฃ18k, ยฃ22k, ยฃ25k, ยฃ24k, ยฃ21k, ยฃ95k, ยฃ23k. Which average should you use?
Solution:
Use the median. The ยฃ95k salary is an outlier (likely the owner/manager).
Mean = (18+22+25+24+21+95+23) รท 7 = 32.6k (misleading)
Median = 23k (better represents typical salary)
A sample of 100 students shows mean study time = 12 hours/week with range = 18 hours. Write a conclusion about study habits.
Solution:
"Students typically spend about 12 hours per week studying, though there is considerable variation (range of 18 hours). Some students study much more than others. This suggests that study habits vary widely among students, possibly due to different subjects, year groups, or personal circumstances."
Compare these two schools' test results:
School A: Mean = 68, Range = 35
School B: Mean = 72, Range = 20
Solution:
"School B performed better on average (mean 72 vs 68). School B's results were more consistent with a smaller range (20 vs 35), suggesting more uniform teaching or student ability. School A has more variation in performance, with some students doing much better or worse than others."
Describing and comparing: report a suitable AVERAGE (mean/median/mode) AND a suitable SPREAD (range/IQR), then interpret both in context.
Compare: Class A mean 62%, range 40; Class B mean 58%, range 12.
A scores higher on average (62 > 58); B is more consistent (range 12 vs 40 โ results less spread out).
B1 for the average comparison, B1 for the spread comparison. BOTH sentences are needed โ 'compare' always means two.
Should a report on house prices use the mean or median? Why?
Median โ a few very expensive houses pull the mean up, so the median better represents a typical price.
B1 with the reason (outliers skew the mean). Median for skewed data, mean for symmetric data.
Exam wording to expect: "compare the distributions", "which average is most appropriate?", "make two comparisons".
Q1: Data has mean = 45, median = 38. Describe the skew of the distribution.
Q2: A survey finds mode = 2 for "number of pets". What does this tell us?
Q3: Why might the median be better than the mean for describing house prices?
Q4: Two classes have test results: Class A (Mean=65, Range=40), Class B (Mean=68, Range=15). Compare them.
Q5: What limitations should you mention when describing a population from sample data?
Q6: Two delivery firms: A mean 32 min, range 18 min; B mean 34 min, range 8 min. Which is more consistent, and which is faster on average?
Q7: Data has mean 20, median 12. Describe the skew and give a possible cause.
Every mark comes from the working, not just the answer. These model answers show the lines a mark scheme expects to see.
Q1. Mean 45 > median 38 โ positive (right) skew โ a few high values pull the mean up
Q2. 2 pets is the most common โ the modal household
Q3. Median โ expensive outliers inflate the mean; the median resists them
Q4. B better on average (68 > 65) and more consistent (range 15 < 40) โ B on both counts
Q5. Sample may not represent the population; estimates carry sampling error; larger samples reduce but never remove it
Q6. B more consistent (8 < 18); B faster on average (34 < 32? no โ A is faster: 32 < 34). Faster = A; consistent = B.
Q7. Mean > median โ positive skew; likely cause: a few unusually large values (e.g. one very high spender)
Comparing distributions: 2โ4 marks on Papers 1/2. Contextual sentences ("Delivered faster on average") score; bare number comparisons do not.
Links to: central tendency (S4), grouped data (S3), scatter (S6).
Spec 8300. Three papers, each 80 marks and 1h30: Paper 1 non-calculator, Papers 2 and 3 calculator. Foundation/Higher tiers. Roughly a third of the marks sit under AO2 (reasoning) and AO3 (problem-solving), so show every line of working โ method marks survive arithmetic slips.
Always check: specification details change โ confirm paper structure and set texts against the current specification for your exam year.
Two towns have house price data: Town A: Mean = ยฃ195,000, Median = ยฃ180,000, IQR = ยฃ60,000. Town B: Mean = ยฃ210,000, Median = ยฃ205,000, IQR = ยฃ40,000. Compare the two towns and describe the distribution in each.
Solution: Town B has higher house prices on average (both mean and median). Town A shows right skew (mean ยฃ195k > median ยฃ180k) โ some expensive houses pull the mean up. Town B is more symmetrical (mean โ median). Town A has more variation (IQR ยฃ60k vs ยฃ40k), so prices in Town A are less consistent. Town B has more uniform pricing.
1. Wrong: Only commenting on the average when comparing distributions, ignoring spread Correct: Always compare BOTH average and spread โ "Town B is higher on average AND more consistent"
2. Wrong: Making definitive statements like "the population mean is exactly 42" from sample data Correct: Use cautious language โ "the sample suggests the population mean is approximately 42"
3. Wrong: Using the mean to describe skewed data without acknowledging it's misleading Correct: For skewed data, the median is more representative โ always note the skew and choose the appropriate average
6 marks: A sample of 150 adults in City X reports: mean commute time = 34 minutes, median = 28 minutes, range = 75 minutes. A sample of 120 adults in City Y reports: mean = 31 minutes, median = 30 minutes, range = 40 minutes. (a) Describe the shape of the distribution for each city. (b) Compare the commute times for the two cities. (c) Ravi says "City X has longer commutes than City Y." Evaluate this claim using both averages.
(a) City X: Mean (34) > Median (28) โ right-skewed, with some very long commutes pulling the mean up. City Y: Mean (31) โ Median (30) โ roughly symmetrical distribution.
(b) City X has slightly higher average commute (mean 34 vs 31, median 28 vs 30). However, the median is actually lower in City X (28 vs 30), suggesting most people in City X have shorter commutes but a few have very long ones. City X has much more variation (range 75 vs 40).
(c) Ravi's claim is partly supported by the mean but contradicted by the median. The mean in City X is higher due to a few extreme values (outliers with very long commutes). The median โ a better measure for skewed data โ is actually lower in City X. So for a "typical" person, City Y has slightly longer commutes. Ravi's claim is misleading because the mean is distorted by outliers.
Mark scheme: M1 for identifying right skew in X, A1 for symmetrical in Y, M1 for comparing both averages, A1 for noting median reversal, M1 for evaluating the claim, A1 for explaining why mean is misleading
A sample of 80 students found: mean number of hours of sleep per night = 7.2, median = 7.5, range = 6. A separate study of 2000 students nationally found mean = 7.8, median = 7.8.
(a) What does the difference between mean and median in the first sample suggest about the distribution?
(b) Can we reliably conclude that these 80 students sleep less than the national average? Give two reasons.
(c) Which study gives a more reliable estimate of the true average? Why?
Get the best revision books and guides to boost your grades.