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G12: 3D Shapes

Foundation Higher AQAEdexcelOCREduqasCCEA

Identify properties of cuboids, prisms, cylinders, pyramids, cones, spheres; faces, surfaces, edges, vertices

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📋 Key Concepts

3D shapes have three dimensions: length, width, and height. They are solid objects that occupy space.
Key terms:
  • Face: A flat surface of a 3D shape
  • Edge: Where two faces meet
  • Vertex (vertices): A corner point where edges meet

📝 Common 3D Shapes

ShapeFacesEdgesVertices
Cube6 (squares)128
Cuboid6 (rectangles)128
Triangular prism596
Square-based pyramid585
Tetrahedron4 (triangles)64
Cylinder3 (2 circles + curved)20
Cone2 (circle + curved)11
Sphere1 (curved)00

📝 Cubes and Cuboids

Cube: All 6 faces are squares. All edges are equal length. 12 edges, 8 vertices.
Cuboid: All 6 faces are rectangles. Opposite faces are equal. 12 edges, 8 vertices.
Example 1

A cuboid has dimensions 4 cm × 3 cm × 2 cm. Find the total length of all edges.

Solution:

A cuboid has 4 edges of each length.

Total = 4(4) + 4(3) + 4(2) = 16 + 12 + 8 = 36 cm

📝 Prisms

Prism: A 3D shape with the same cross-section throughout. The end faces are identical polygons, and the other faces are rectangles.
Types of prisms:
  • Triangular prism
  • Rectangular prism (cuboid)
  • Pentagonal prism
  • Hexagonal prism
Example 2

How many edges does a hexagonal prism have?

Solution:

Each hexagonal face has 6 edges.

There are 6 rectangular faces joining them.

Total edges = 6 + 6 + 6 = 18 edges

📝 Pyramids

Pyramid: A 3D shape with a polygon base and triangular faces meeting at a point (apex).
Square-based pyramid: 5 faces (1 square + 4 triangles), 8 edges, 5 vertices.
Tetrahedron (triangular-based pyramid): 4 triangular faces, 6 edges, 4 vertices.

📝 Cylinders, Cones and Spheres

Cylinder: 2 circular faces and 1 curved surface. 2 edges (the circles), no vertices.
Cone: 1 circular face and 1 curved surface. 1 edge (the circle), 1 vertex (the apex).
Sphere: A perfectly round 3D shape. 1 curved face, no edges, no vertices.
Example 3

Name a 3D shape with exactly one vertex.

Solution: A cone has exactly one vertex (the apex).

📝 Euler's Formula

Euler's Formula: For polyhedra (3D shapes with flat faces):
F + V - E = 2

Where F = number of faces, V = number of vertices, E = number of edges

Example 4

Verify Euler's formula for a cube.

Solution:

F = 6, V = 8, E = 12

F + V - E = 6 + 8 - 12 = 2 ✓

❓ Practice Questions

Q1: How many faces does a triangular prism have?

Q2: Name a 3D shape with no vertices.

Q3: How many edges does a square-based pyramid have?

Q4: What shape has 6 rectangular faces?

Q5: Verify Euler's formula for a tetrahedron.

✅ Answers

  1. 5 faces (2 triangles + 3 rectangles)
  2. Sphere or cylinder
  3. 8 edges
  4. Cuboid (or rectangular prism)
  5. F = 4, V = 4, E = 6. F + V - E = 4 + 4 - 6 = 2 ✓

🎯 Exam Tips

🧠 Problem-Solving Strategies

Problem-Solving

Visualise 3D shapes by identifying faces, edges and vertices. Euler's formula: V - E + F = 2 for any convex polyhedron. For prisms: V = area of cross-section x length. For pyramids: V = 1/3 x base area x height. Use Pythagoras in 3D to find diagonal lengths by working through right-angled triangles.
Multi-Step Problem

A cuboid measures 4 cm by 3 cm by 12 cm. Find the length of its space diagonal (from one vertex to the opposite vertex).

Solution: First find the diagonal of the base: sqrt(4 squared + 3 squared) = sqrt(16 + 9) = 5 cm. Then the space diagonal = sqrt(5 squared + 12 squared) = sqrt(25 + 144) = sqrt(169) = 13 cm. Alternatively: sqrt(4 squared + 3 squared + 12 squared) = sqrt(16 + 9 + 144) = sqrt(169) = 13 cm.

⚠️ Common Errors

Watch Out!

1. Wrong: Calculating the volume of a pyramid as base area x height Correct: Volume of a pyramid = 1/3 x base area x height. The 1/3 is essential — a pyramid has one-third the volume of a prism with the same base and height.

2. Wrong: Forgetting that a cone is NOT a pyramid (different formula) Correct: A cone uses V = 1/3 x pi x r squared x h. A pyramid uses V = 1/3 x base area x h. The formulas are similar but the base shapes differ.

3. Wrong: Counting faces, edges or vertices incorrectly for complex polyhedra Correct: Count systematically. For a prism: F = n + 2, E = 3n, V = 2n where n = number of sides of the cross-section. Verify with Euler's formula: V - E + F = 2.

✍️ 6-Mark Exam Question

Extended Answer

6 marks: A solid is formed by placing a square-based pyramid on top of a cuboid. The cuboid has dimensions 6 cm x 6 cm x 8 cm. The pyramid has the same square base (6 cm x 6 cm) and a vertical height of 4 cm. (a) Find the volume of the combined solid. (b) Find the total surface area. (c) A sphere has the same volume as the combined solid. Find its radius to 1 decimal place.

(a) Cuboid volume = 6 x 6 x 8 = 288 cm cubed. Pyramid volume = 1/3 x 36 x 4 = 48 cm cubed. Total = 336 cm cubed.

(b) Cuboid SA (without top) = 4 x (6 x 8) + 6 x 6 = 192 + 36 = 228 cm squared. Pyramid: slant height = sqrt(9 + 16) = 5 cm. 4 triangular faces = 4 x 1/2 x 6 x 5 = 60 cm squared. Total SA = 228 + 60 = 288 cm squared.

(c) V = 4/3 x pi x r cubed = 336. r cubed = 336 x 3/(4 x pi) = 80.19. r = 4.3 cm (1 d.p.).

Mark scheme: M1 cuboid volume, A1 288, M1 pyramid volume, A1 total 336, M1 surface area components, A1 288, M1 sphere formula, A1 r = 4.3

📊 AO3: Reason & Interpret

Reasoning and Interpretation

A water tank is a cylinder with radius 30 cm and height 80 cm. Water is pumped in at 2 litres per minute.

(a) How long does it take to fill the tank? (1 litre = 1000 cm cubed)

(b) The tank is filled to a depth of 20 cm. A metal cube of side 15 cm is lowered into the water. By how much does the water level rise?

(c) A student says "A sphere with radius 30 cm would hold the same amount of water as this cylinder." Is this correct? Compare the volumes.

Answers: (a) Volume = pi x 30 squared x 80 = 72000pi cm cubed = 226,195 cm cubed = 226.2 litres. Time = 226.2/2 = 113.1 minutes (about 1 hour 53 minutes). (b) Cube volume = 15 cubed = 3375 cm cubed. Rise = 3375/(pi x 30 squared) = 3375/(900pi) = 1.19 cm. (c) Sphere volume = 4/3 x pi x 30 cubed = 36000pi. Cylinder = 72000pi. The sphere holds exactly HALF the cylinder. The student is wrong.

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