GCSE Revision Aid: This resource is designed to support your revision and may contain errors. If you find a discrepancy with your class teaching, your teacher is correct — please let us know at gcserevise@scott.scottrix.co.uk.

N8: Surds

Higher Only AQAEdexcelOCREduqasCCEA

Calculate exactly with fractions, multiples of π; simplify surds, rationalise denominators

Fastmail

📋 Key Concepts

What is a Surd? A surd is an irrational square root that cannot be written as an exact decimal. Examples: √2, √3, √5, √6...
Important: √4 = 2 is NOT a surd (it's rational). √2 ≈ 1.414... is a surd (it's irrational and cannot be written exactly).
Key Surd Rules:
√(a × b) = √a × √b
√(a ÷ b) = √a ÷ √b
(√a)² = a
√a² = a (for a ≥ 0)

📝 Simplifying Surds

Method: Find the largest square number that divides into the surd. Split it and simplify.
Example 1

Simplify: √12

Solution:

√12 = √(4 × 3) = √4 × √3 = 2√3

Example 2

Simplify: √50

Solution:

√50 = √(25 × 2) = √25 × √2 = 5√2

Example 3

Simplify: √72

Solution:

√72 = √(36 × 2) = √36 × √2 = 6√2

Alternative: √72 = √(9 × 8) = 3√8 = 3 × 2√2 = 6√2

📝 Adding and Subtracting Surds

Rule: Only "like surds" can be added or subtracted. Simplify first, then combine like terms.
Example 4

Simplify: √12 + √27

Solution:

√12 = 2√3 and √27 = 3√3

2√3 + 3√3 = 5√3

Example 5

Simplify: 3√20 - √45

Solution:

√20 = 2√5, so 3√20 = 6√5

√45 = 3√5

6√5 - 3√5 = 3√5

📝 Multiplying Surds

Rule: Multiply surds by multiplying the numbers inside: √a × √b = √(a × b)
Example 6

Simplify: √2 × √8

Solution:

√2 × √8 = √16 = 4

Example 7

Expand: √3(2 + √12)

Solution:

√3 × 2 = 2√3

√3 × √12 = √36 = 6

Answer: 6 + 2√3

📝 Rationalising Denominators

Why? A fraction should not have a surd in the denominator. Multiply top and bottom to remove it.

Simple Denominators

Method: If the denominator is √a, multiply top and bottom by √a.
Example 8

Rationalise: 1/√2

Solution:

Multiply by √2/√2:

1/√2 × √2/√2 = √2/2

Example 9

Rationalise: 6/√3

Solution:

6/√3 × √3/√3 = 6√3/3 = 2√3

Complex Denominators

Method: If the denominator is a ± √b, multiply by the "conjugate" a ∓ √b.
Example 10

Rationalise: 1/(2 + √3)

Solution:

Multiply by (2 - √3)/(2 - √3):

1(2 - √3) / [(2 + √3)(2 - √3)]

= (2 - √3) / (4 - 3)

= (2 - √3) / 1 = 2 - √3

Example 11

Rationalise: 5/(3 - √2)

Solution:

Multiply by (3 + √2)/(3 + √2):

5(3 + √2) / [(3 - √2)(3 + √2)]

= 5(3 + √2) / (9 - 2)

= 5(3 + √2) / 7 = (15 + 5√2)/7

📝 Exact Values with π

Exact values: Leave answers in terms of π when asked for exact values.
Example 12

Find the exact area of a circle with radius 5 cm

Solution:

A = πr² = π × 5² = 25π cm²

Do NOT calculate 25 × 3.14... - leave as 25π

❓ Practice Questions

Q1: Simplify: √75

Q2: Simplify: √18 - √8

Q3: Simplify: 2√5 × 3√10

Q4: Rationalise: 3/√5

Q5: Rationalise: 2/(1 + √3)

✅ Answers

  1. √75 = √(25 × 3) = 5√3
  2. √18 = 3√2, √8 = 2√2, so 3√2 - 2√2 = √2
  3. 2 × 3 × √50 = 6 × 5√2 = 30√2
  4. 3/√5 × √5/√5 = 3√5/5
  5. 2(1 - √3)/(1 - 3) = 2(1 - √3)/(-2) = √3 - 1

🎯 Exam Tips

🧠 Problem-Solving Strategies

Problem-Solving

For surd problems, always simplify first before combining. When rationalising, identify whether the denominator is a simple surd (multiply by √a) or a bracketed expression (multiply by the conjugate). For exact value problems, never convert to decimals — leave answers in surd form or in terms of π.
Multi-Step Problem

A rectangle has length 2 + √3 and width 2 − √3. Show that the area is an integer, and find the perimeter in simplified surd form.

Solution: Area = (2 + √3)(2 − √3) = 4 − 3 = 1 (integer ✓). Perimeter = 2(2 + √3) + 2(2 − √3) = 4 + 2√3 + 4 − 2√3 = 8.

⚠️ Common Errors

Watch Out!

1. Wrong: √12 + √3 = √15 (adding inside one square root) Correct: √12 = 2√3, so √12 + √3 = 2√3 + √3 = 3√3

2. Wrong: √(a + b) = √a + √b Correct: √(a + b) ≠ √a + √b — you cannot split a square root over addition

3. Wrong: Rationalising 1/(3 + √2) by multiplying by √2/√2 Correct: Multiply by the conjugate (3 − √2)/(3 − √2) to eliminate the surd from the denominator

✍️ 6-Mark Exam Question

Extended Answer

6 marks: (a) Simplify √28 − √63 + √175. (b) Rationalise the denominator of 4/(3 − √5). (c) Show that (2 + √5)² = 9 + 4√5. Hence find the exact value of (2 + √5)² + (2 − √5)².

(a) √28 = 2√7, √63 = 3√7, √175 = 5√7. So 2√7 − 3√7 + 5√7 = 4√7.

(b) 4/(3 − √5) × (3 + √5)/(3 + √5) = 4(3 + √5)/(9 − 5) = 4(3 + √5)/4 = 3 + √5.

(c) (2 + √5)² = 4 + 4√5 + 5 = 9 + 4√5 ✓. By symmetry, (2 − √5)² = 9 − 4√5. Sum = 9 + 4√5 + 9 − 4√5 = 18.

Mark scheme: 2 marks for (a) with full simplification, 2 marks for (b) with correct conjugate method, 2 marks for (c) including the sum

📊 AO3: Reason & Interpret

Reasoning and Interpretation

A right-angled triangle has legs of length √8 cm and √18 cm.

(a) Show that the hypotenuse has exact length √26 cm.

(b) A student says "The hypotenuse is √8 + √18 = 2√2 + 3√2 = 5√2 cm." Explain why this is wrong.

(c) Compare the exact hypotenuse with the student's answer. Which is longer?

Answers: (a) By Pythagoras: hyp² = √8² + √18² = 8 + 18 = 26, so hyp = √26 cm. (b) The student added the legs, but Pythagoras' theorem requires SQUARING the legs first, then adding, then square rooting. You cannot just add the sides. (c) √26 ≈ 5.10, 5√2 ≈ 7.07. The student's answer is longer, which shows adding sides gives an overestimate of the hypotenuse.

📝 Exam Questions by Topic

🎬 Video Resources

Share this page

Ready to ace your GCSE Mathematics exams?

Get the best revision books and guides to boost your grades.