N8: Surds
Calculate exactly with fractions, multiples of π; simplify surds, rationalise denominators
Calculate exactly with fractions, multiples of π; simplify surds, rationalise denominators
Simplify: √12
Solution:
√12 = √(4 × 3) = √4 × √3 = 2√3
Simplify: √50
Solution:
√50 = √(25 × 2) = √25 × √2 = 5√2
Simplify: √72
Solution:
√72 = √(36 × 2) = √36 × √2 = 6√2
Alternative: √72 = √(9 × 8) = 3√8 = 3 × 2√2 = 6√2
Simplify: √12 + √27
Solution:
√12 = 2√3 and √27 = 3√3
2√3 + 3√3 = 5√3
Simplify: 3√20 - √45
Solution:
√20 = 2√5, so 3√20 = 6√5
√45 = 3√5
6√5 - 3√5 = 3√5
Simplify: √2 × √8
Solution:
√2 × √8 = √16 = 4
Expand: √3(2 + √12)
Solution:
√3 × 2 = 2√3
√3 × √12 = √36 = 6
Answer: 6 + 2√3
Rationalise: 1/√2
Solution:
Multiply by √2/√2:
1/√2 × √2/√2 = √2/2
Rationalise: 6/√3
Solution:
6/√3 × √3/√3 = 6√3/3 = 2√3
Rationalise: 1/(2 + √3)
Solution:
Multiply by (2 - √3)/(2 - √3):
1(2 - √3) / [(2 + √3)(2 - √3)]
= (2 - √3) / (4 - 3)
= (2 - √3) / 1 = 2 - √3
Rationalise: 5/(3 - √2)
Solution:
Multiply by (3 + √2)/(3 + √2):
5(3 + √2) / [(3 - √2)(3 + √2)]
= 5(3 + √2) / (9 - 2)
= 5(3 + √2) / 7 = (15 + 5√2)/7
Find the exact area of a circle with radius 5 cm
Solution:
A = πr² = π × 5² = 25π cm²
Do NOT calculate 25 × 3.14... - leave as 25π
Q1: Simplify: √75
Q2: Simplify: √18 - √8
Q3: Simplify: 2√5 × 3√10
Q4: Rationalise: 3/√5
Q5: Rationalise: 2/(1 + √3)
A rectangle has length 2 + √3 and width 2 − √3. Show that the area is an integer, and find the perimeter in simplified surd form.
Solution: Area = (2 + √3)(2 − √3) = 4 − 3 = 1 (integer ✓). Perimeter = 2(2 + √3) + 2(2 − √3) = 4 + 2√3 + 4 − 2√3 = 8.
1. Wrong: √12 + √3 = √15 (adding inside one square root) Correct: √12 = 2√3, so √12 + √3 = 2√3 + √3 = 3√3
2. Wrong: √(a + b) = √a + √b Correct: √(a + b) ≠ √a + √b — you cannot split a square root over addition
3. Wrong: Rationalising 1/(3 + √2) by multiplying by √2/√2 Correct: Multiply by the conjugate (3 − √2)/(3 − √2) to eliminate the surd from the denominator
6 marks: (a) Simplify √28 − √63 + √175. (b) Rationalise the denominator of 4/(3 − √5). (c) Show that (2 + √5)² = 9 + 4√5. Hence find the exact value of (2 + √5)² + (2 − √5)².
(a) √28 = 2√7, √63 = 3√7, √175 = 5√7. So 2√7 − 3√7 + 5√7 = 4√7.
(b) 4/(3 − √5) × (3 + √5)/(3 + √5) = 4(3 + √5)/(9 − 5) = 4(3 + √5)/4 = 3 + √5.
(c) (2 + √5)² = 4 + 4√5 + 5 = 9 + 4√5 ✓. By symmetry, (2 − √5)² = 9 − 4√5. Sum = 9 + 4√5 + 9 − 4√5 = 18.
Mark scheme: 2 marks for (a) with full simplification, 2 marks for (b) with correct conjugate method, 2 marks for (c) including the sum
A right-angled triangle has legs of length √8 cm and √18 cm.
(a) Show that the hypotenuse has exact length √26 cm.
(b) A student says "The hypotenuse is √8 + √18 = 2√2 + 3√2 = 5√2 cm." Explain why this is wrong.
(c) Compare the exact hypotenuse with the student's answer. Which is longer?
Get the best revision books and guides to boost your grades.