A7: Functions
Work with functions and their inverses; composite functions; f(x), fg(x), f⁻¹(x) notation
📋 Key Concepts
Function: A rule that takes an input (x) and gives exactly one output. Written as f(x), g(x), etc.
Notation:
f(x) means "function f of x"
f(3) means "substitute x = 3 into function f"
f(x) means "function f of x"
f(3) means "substitute x = 3 into function f"
Key terms:
- Domain: All possible input values
- Range: All possible output values
📝 Evaluating Functions
Example 1
Given f(x) = 3x - 2, find:
a) f(4)
b) f(-2)
c) f(a)
Solution:
a) f(4) = 3(4) - 2 = 12 - 2 = 10
b) f(-2) = 3(-2) - 2 = -6 - 2 = -8
c) f(a) = 3a - 2
Example 2
Given g(x) = x² + 1, find:
a) g(3)
b) g(-3)
c) g(2x)
Solution:
a) g(3) = 3² + 1 = 10
b) g(-3) = (-3)² + 1 = 10
c) g(2x) = (2x)² + 1 = 4x² + 1
📝 Inverse Functions
Inverse function f⁻¹(x): The function that "undoes" f. If f(a) = b, then f⁻¹(b) = a.
Method to find f⁻¹(x):
- Write y = f(x)
- Make x the subject
- Replace y with x
Example 3
Find f⁻¹(x) when f(x) = 3x + 5
Solution:
Step 1: Let y = 3x + 5
Step 2: Make x the subject:
y - 5 = 3x
x = y - 5⁄3
Step 3: Replace y with x:
f⁻¹(x) = x - 5⁄3
Example 4
Find f⁻¹(x) when f(x) = x + 3⁄2
Solution:
y = x + 3⁄2
2y = x + 3
x = 2y - 3
f⁻¹(x) = 2x - 3
📝 Composite Functions
Composite function fg(x): Apply g first, then apply f to the result. fg(x) = f(g(x))
Order matters: fg(x) ≠ gf(x) in general. Always work from the inside out.
Example 5
Given f(x) = 2x + 1 and g(x) = x², find:
a) fg(3)
b) gf(3)
Solution:
a) fg(3) = f(g(3)) = f(3²) = f(9) = 2(9) + 1 = 19
b) gf(3) = g(f(3)) = g(2(3) + 1) = g(7) = 7² = 49
Example 6
Given f(x) = x + 4 and g(x) = 2x - 1, find fg(x)
Solution:
fg(x) = f(g(x))
= f(2x - 1)
= (2x - 1) + 4
= 2x + 3
Example 7
Given f(x) = 3x and g(x) = x - 2, find gf(x)
Solution:
gf(x) = g(f(x))
= g(3x)
= 3x - 2
📝 Harder Inverse Functions
Example 8
Find f⁻¹(x) when f(x) = x² + 5, x ≥ 0
Solution:
y = x² + 5
y - 5 = x²
x = √(y - 5)
f⁻¹(x) = √(x - 5), x ≥ 5
🧮 Worked Examples — Exam Style
Function machines: f(x) is the rule. Composite fg(x) means 'g FIRST, then f' — work from the inside out.
Given f(x) = 2x + 1, find f(−3).
f(−3) = 2(−3) + 1 = −6 + 1 = −5
B1 for −5. Substitution with brackets — the (−3) gets multiplied by 2, not the 3.
Find the inverse of f(x) = 3x + 6.
Rearrange: y = 3x + 6 → x = (y − 6)/3
f⁻¹(x) = (x − 6)/3
M1 for swapping/rearranging, A1 for (x − 6)/3. Check with a value: f(2) = 12 and f⁻¹(12) = 2 ✓
Exam wording to expect: "Find f(…)", "Find the inverse function", "Find fg(…)".
❓ Practice Questions
Q1: Given f(x) = 4x - 3, find f(5) and f(-2).
Q2: Given g(x) = x² - 1, find g(3) and g(x + 1).
Q3: Find the inverse of f(x) = 2x - 7.
Q4: Find the inverse of g(x) = x⁄4 + 1.
Q5: Given f(x) = x + 3 and g(x) = 2x, find fg(x) and gf(x).
Q6: Given f(x) = x² and g(x) = x + 1, find fg(2) and gf(2).
Q7: Given f(x) = 3x − 1 and g(x) = x², find fg(3)
Q8: Find the inverse of h(x) = (x + 2)/5
✅ Answers
- f(5) = 17, f(-2) = -11
- g(3) = 8, g(x + 1) = (x + 1)² - 1 = x² + 2x
- f⁻¹(x) = x + 7⁄2
- g⁻¹(x) = 4(x - 1) = 4x - 4
- fg(x) = 2x + 3, gf(x) = 2(x + 3) = 2x + 6
- fg(2) = f(g(2)) = f(3) = 9, gf(2) = g(f(2)) = g(4) = 5
📋 Model Answers — Full Working
Every mark comes from the working, not just the answer. These model answers show the lines a mark scheme expects to see.
Q1. f(5) = 20 − 3 = 17; f(−2) = −8 − 3 = −11
Q2. g(3) = 9 − 1 = 8; g(x + 1) = (x + 1)² − 1 = x² + 2x + 1 − 1 = x² + 2x
Q3. y = 2x − 7 → x = (y + 7)/2 → f⁻¹(x) = (x + 7)/2
Q4. y = x/4 + 1 → x = 4(y − 1) → g⁻¹(x) = 4x − 4
Q5. fg(x) = f(2x) = 2(2x) + 3 = 4x + 3; gf(x) = g(x + 3) = 2(x + 3) = 2x + 6
Q6. fg(2) = f(3) = 9; gf(2) = g(4) = 5 — order matters!
Q7. g(3) = 9, then f(9) = 27 − 1 = 26
Q8. y = (x + 2)/5 → x = 5y − 2 → h⁻¹(x) = 5x − 2
📌 Key Facts to Memorise
- f(x) = the rule; f(3) = substitute 3 for x
- fg(x) = f(g(x)): g runs FIRST, f second (read right to left)
- Inverse: swap x and y, then rearrange — undoes the original
- f(f⁻¹(x)) = x — use as a check
- Two-step functions invert in reverse order: ×2 then +1 inverts as −1 then ÷2
🗺️ In the Exam
Functions: 2–4 marks. Inverses appear on Paper 1; composites on Paper 2/3. The "which order?" trap in composites is the discriminator.
Links to: substitution (A2), rearranging (A5), solving equations (A17).
🧭 Board Focus — OCR
Spec J560. Three papers of 100 marks each: Paper 1 non-calculator, Papers 2 and 3 calculator, at Foundation/Higher tiers. OCR marks problem-solving explicitly, and its papers tend to front-load multi-step worded contexts — practise extracting the mathematics from prose before calculating.
Always check: specification details change — confirm paper structure and set texts against the current specification for your exam year.
🎯 Exam Tips
- For composite functions, work from inside out: fg(x) means f(g(x))
- To find inverse, swap x and y, then make y the subject
- Check your inverse: f(f⁻¹(x)) should equal x
- Domain restrictions may apply to inverse functions
- Read carefully: fg(x) ≠ gf(x)
🧠 Problem-Solving Strategies
Problem-Solving
For composite functions, always work from the inside out. For inverse functions, swap x and y then make y the subject. Verify inverses by checking f(f⁻¹(x)) = x. Pay close attention to order — fg(x) means apply g first.
Multi-Step Problem
Given f(x) = 2x + 1 and g(x) = x². (a) Find ff(3). (b) Find f⁻¹(x). (c) Solve fg(x) = 33.
Solution:
(a) f(3) = 7, then f(7) = 15
(b) y = 2x + 1 → x = y - 1⁄2, so f⁻¹(x) = x - 1⁄2
(c) fg(x) = f(x²) = 2x² + 1 = 33 → 2x² = 32 → x² = 16 → x = ±4
⚠️ Common Errors
Watch Out!
1. Wrong: fg(x) means f × g(x) Correct: fg(x) = f(g(x)) — apply g first, then f to the result
2. Wrong: f⁻¹(x) means 1⁄f(x) Correct: f⁻¹(x) is the inverse function, not the reciprocal
3. Wrong: fg(x) = gf(x) always Correct: Order matters! fg(x) ≠ gf(x) in general
✍️ 6-Mark Exam Question
Extended Answer
6 marks: f(x) = 3x - 5 and g(x) = x + 2⁄4. (a) Find f⁻¹(x). (b) Find gf(3). (c) Show that fg(x) ≠ gf(x) by finding both expressions.
(a) y = 3x - 5 → y + 5 = 3x → x = y + 5⁄3, so f⁻¹(x) = x + 5⁄3
(b) f(3) = 3(3) - 5 = 4. g(4) = 4 + 2⁄4 = 6⁄4 = 1.5
(c) fg(x) = f(x + 2⁄4) = 3(x + 2⁄4) - 5 = 3x + 6⁄4 - 5 = 3x - 14⁄4
gf(x) = g(3x - 5) = 3x - 5 + 2⁄4 = 3x - 3⁄4
These are different: 3x - 14⁄4 ≠ 3x - 3⁄4
Mark scheme: (a) 2 marks. (b) 1 mark for f(3), 1 mark for final answer. (c) 1 mark for fg(x), 1 mark for gf(x).
📊 AO3: Reason & Interpret
Reasoning and Interpretation
f(x) = 2x + 3 converts a temperature from °C to an adjusted scale. g(x) = x - 3⁄2 is its inverse.
(a) What does f(0) represent?
(b) If the output of f is 15, what was the input?
(c) Explain why g undoes f.
Answers: (a) f(0) = 3 — the adjusted value when the input is 0°C. (b) f⁻¹(15) = 15 - 3⁄2 = 6. (c) gf(x) = g(2x+3) = 2x+3-3⁄2 = x. So applying g after f returns the original value.
📝 Exam Questions by Topic
🎬 Video Resources
Ready to ace your GCSE Mathematics exams?
Get the best revision books and guides to boost your grades.