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N9: Standard Form

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Calculate with numbers in standard form A × 10^n where 1 ≤ A < 10

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📋 Key Concepts

Standard Form: A way of writing very large or very small numbers. The format is A × 10ⁿ where 1 ≤ A < 10 and n is an integer.
Standard Form Rules:
• A must be between 1 and 10 (1 ≤ A < 10)
• n is positive for large numbers, negative for small numbers
• The × 10ⁿ part tells you how far to move the decimal point
NumberStandard Formn value
30003 × 10³Positive (large)
52,0005.2 × 10⁴Positive (large)
0.0044 × 10⁻³Negative (small)
0.000525.2 × 10⁻⁴Negative (small)

📝 Converting to Standard Form

Method: Count how many places the decimal point moves to get A between 1 and 10.
Example 1

Write 45,000 in standard form

Solution:

Move decimal point left: 4.5 (need A between 1 and 10)

Moved 4 places: 4.5 × 10⁴

Example 2

Write 0.00073 in standard form

Solution:

Move decimal point right: 7.3

Moved 4 places: 7.3 × 10⁻⁴

📝 Converting from Standard Form

Method: Positive n → move decimal right. Negative n → move decimal left.
Example 3

Write 5.4 × 10⁵ as an ordinary number

Solution:

Positive exponent → large number

Move decimal 5 places right: 540,000

Example 4

Write 3.2 × 10⁻³ as an ordinary number

Solution:

Negative exponent → small number

Move decimal 3 places left: 0.0032

📝 Multiplying in Standard Form

Method: Multiply the A parts, add the powers of 10, then adjust to proper standard form.
Example 5

Calculate: (2 × 10⁴) × (3 × 10⁵)

Solution:

2 × 3 = 6

10⁴ × 10⁵ = 10⁹

Answer: 6 × 10⁹

Example 6

Calculate: (4 × 10³) × (2 × 10⁴)

Solution:

4 × 2 = 8

10³ × 10⁴ = 10⁷

Answer: 8 × 10⁷

Example 7

Calculate: (5 × 10³) × (4 × 10²)

Solution:

5 × 4 = 20

10³ × 10² = 10⁵

20 × 10⁵ = 2 × 10⁶ (adjust to standard form)

📝 Dividing in Standard Form

Method: Divide the A parts, subtract the powers of 10, then adjust to proper standard form.
Example 8

Calculate: (6 × 10⁸) ÷ (2 × 10³)

Solution:

6 ÷ 2 = 3

10⁸ ÷ 10³ = 10⁵

Answer: 3 × 10⁵

Example 9

Calculate: (8 × 10⁶) ÷ (4 × 10⁻²)

Solution:

8 ÷ 4 = 2

10⁶ ÷ 10⁻² = 10⁸

Answer: 2 × 10⁸

📝 Adding and Subtracting

Method: Convert to ordinary numbers, calculate, then convert back to standard form. Or make the powers of 10 the same first.
Example 10

Calculate: (3.2 × 10⁴) + (5.1 × 10³)

Solution:

Convert: 32,000 + 5,100 = 37,100

Back to standard form: 3.71 × 10⁴

❓ Practice Questions

Q1: Write 7,500,000 in standard form

Q2: Write 0.000082 in standard form

Q3: Write 4.7 × 10⁻² as an ordinary number

Q4: Calculate: (3 × 10⁵) × (4 × 10⁶)

Q5: Calculate: (9 × 10⁸) ÷ (3 × 10²)

✅ Answers

  1. 7.5 × 10⁶
  2. 8.2 × 10⁻⁵
  3. 0.047
  4. 12 × 10¹¹ = 1.2 × 10¹²
  5. 3 × 10⁶

🎯 Exam Tips

🧠 Problem-Solving Strategies

Problem-Solving

For standard form calculations, multiply/divide the A parts and powers of 10 separately, then adjust so A is between 1 and 10. For addition/subtraction, convert to ordinary numbers first or equalise the powers. Always check your final answer is in proper standard form (1 ≤ A < 10).
Multi-Step Problem

The population of Country A is 6.2 × 10⁷ and Country B is 8.4 × 10⁶. How many times larger is Country A's population? Give your answer to 2 significant figures.

Solution: Ratio = (6.2 × 10⁷) ÷ (8.4 × 10⁶) = (6.2 ÷ 8.4) × 10¹ = 0.738... × 10 = 7.38... ≈ 7.4 times.

⚠️ Common Errors

Watch Out!

1. Wrong: 12 × 10³ is in standard form Correct: A must be between 1 and 10, so 12 × 10³ = 1.2 × 10⁴

2. Wrong: 0.3 × 10⁵ is in standard form Correct: A must be ≥ 1, so 0.3 × 10⁵ = 3 × 10⁴

3. Wrong: When adding (3 × 10⁴) + (2 × 10³) = 5 × 10⁷ Correct: Convert first: 30,000 + 2,000 = 32,000 = 3.2 × 10⁴

✍️ 6-Mark Exam Question

Extended Answer

6 marks: The distance from Earth to the Sun is 1.5 × 10⁸ km. Light travels at 3.0 × 10⁵ km/s. (a) Calculate how many seconds it takes light to travel from the Sun to Earth. Give your answer in standard form. (b) Convert your answer to minutes. (c) A star is 4.2 × 10¹³ km from Earth. How many years does light from this star take to reach Earth? (1 year = 3.15 × 10⁷ seconds)

(a) Time = distance ÷ speed = (1.5 × 10⁸) ÷ (3.0 × 10⁵) = 0.5 × 10³ = 5.0 × 10² seconds.

(b) 5.0 × 10² ÷ 60 = 500 ÷ 60 = 8.33 minutes.

(c) Time = (4.2 × 10¹³) ÷ (3.0 × 10⁵) = 1.4 × 10⁸ seconds. Years = (1.4 × 10⁸) ÷ (3.15 × 10⁷) = 1.4/3.15 × 10 = 4.44 years.

Mark scheme: 2 marks for (a) including standard form adjustment, 1 mark for (b), 3 marks for (c) with clear working and unit conversion

📊 AO3: Reason & Interpret

Reasoning and Interpretation

The mass of the Earth is 5.97 × 10²⁴ kg. The mass of Jupiter is 1.9 × 10²⁷ kg.

(a) How many times more massive is Jupiter than Earth? Give your answer to 1 significant figure.

(b) A student says "Jupiter is about 3000 times more massive than Earth." Is this a reasonable claim?

(c) The Sun's mass is 1.99 × 10³⁰ kg. Express the combined mass of Earth and Jupiter as a fraction of the Sun's mass.

Answers: (a) (1.9 × 10²⁷) ÷ (5.97 × 10²⁴) = (1.9/5.97) × 10³ ≈ 0.318 × 1000 ≈ 318 ≈ 300 (1 s.f.). (b) The student said 3000, but the answer is about 300. The student is off by a factor of 10 — they likely miscalculated the power of 10. (c) Combined = 5.97 × 10²⁴ + 1.9 × 10²⁷ ≈ 1.906 × 10²⁷ kg. Fraction = (1.906 × 10²⁷)/(1.99 × 10³⁰) ≈ 9.58 × 10⁻⁴ ≈ 0.001.

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