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P5: Circuit Basics

FoundationHigher AQAEdexcelOCRCCEA

Standard circuit symbols, current, voltage and resistance — Ohm's Law and I-V characteristics.

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📋 Key Definitions

Electric current: The rate of flow of charge. Measured in amperes (A) using an ammeter connected in series. Current is the same in all parts of a series circuit.
Potential difference (voltage): The energy transferred per unit charge passing between two points. Measured in volts (V) using a voltmeter connected in parallel across the component.
Resistance: The opposition to the flow of current. Measured in ohms (Ω). Higher resistance means less current for a given voltage.

🔌 Standard Circuit Symbols

ComponentSymbol DescriptionKey Detail
CellLong line (+) and short thick line (-)Provides energy to the circuit
BatteryTwo or more cells joined togetherLong line = positive terminal
Switch (open)Gap in the circuit lineCircuit is incomplete — no current
Switch (closed)Line completes the circuitCircuit is complete — current flows
LampCircle with a cross insideConverts electrical energy to light
ResistorRectangleOpposes current flow at constant rate
Variable resistorRectangle with diagonal arrowResistance can be changed
AmmeterCircle with 'A' insideConnected in series, measures current
VoltmeterCircle with 'V' insideConnected in parallel, measures voltage
DiodeTriangle pointing to a lineCurrent flows in one direction only
LEDTriangle with arrows (light)Diode that emits light when forward biased
FuseRectangle with line through itMelts if current is too high, breaks circuit
ThermistorRectangle with 't' or diagonal lineResistance decreases as temperature increases
LDRCircle with arrows, rectangle insideResistance decreases as light intensity increases

📐 Ohm's Law

Ohm's Law: The current through a resistor at constant temperature is directly proportional to the potential difference across it. This means V = I x R.
V = I x R

Where:

R = V / I
I = V / R

📊 I-V Characteristics

Required practical: Investigate the I-V characteristics of a resistor, a filament lamp and a diode to see how current varies with potential difference.
ComponentI-V Graph ShapeExplanation
Resistor (at constant temperature)Straight line through originCurrent is directly proportional to voltage (Ohmic conductor). Resistance is constant.
Filament lampCurve that flattens at higher voltagesAs current increases, the filament heats up, resistance increases, so current increases less quickly. Not an Ohmic conductor.
DiodeCurrent only in forward direction; zero in reverseDiode only conducts when forward biased (positive to the anode). Very high resistance in reverse direction.

Method for I-V Characteristics Practical

  1. Set up a circuit with a variable resistor (or variable power supply), ammeter in series, and voltmeter in parallel across the component.
  2. Vary the potential difference across the component from 0 V upwards in small steps.
  3. Record the current at each voltage.
  4. Repeat for negative voltages (reverse the power supply connections).
  5. Plot a graph of current (y-axis) against voltage (x-axis).

🌡️ Thermistors and LDRs

ComponentConditionResistanceCurrent
ThermistorTemperature increasesResistance decreasesCurrent increases
Temperature decreasesResistance increasesCurrent decreases
LDRLight intensity increasesResistance decreasesCurrent increases
Light intensity decreasesResistance increasesCurrent decreases
Applications: Thermistors are used in temperature sensors (e.g. thermostats, car engine temperature sensors). LDRs are used in light sensors (e.g. automatic street lights, burglar alarms, camera light meters).

📝 Worked Examples

Worked Example 1 — Using Ohm's Law to find Voltage

Question: A resistor has a resistance of 10 Ω and a current of 3 A flows through it. Calculate the potential difference across the resistor.

Solution:

V = I x R = 3 x 10 = 30 V
Worked Example 2 — Using Ohm's Law to find Resistance

Question: A lamp has a potential difference of 12 V across it and a current of 0.5 A flows through it. Calculate the resistance of the lamp.

Solution:

R = V / I = 12 / 0.5 = 24 Ω
Worked Example 3 — Using Ohm's Law to find Current

Question: A 220 Ω resistor is connected to a 6 V battery. Calculate the current flowing through it.

Solution:

I = V / R = 6 / 220 = 0.027 A = 27 mA
Worked Example 4 — Thermistor Calculation

Question: A thermistor has a resistance of 5000 Ω at 20 °C. When heated to 80 °C its resistance drops to 200 Ω. It is connected to a 9 V battery. Calculate the current at each temperature.

Solution:

At 20 °C: I = V / R = 9 / 5000 = 0.0018 A = 1.8 mA

At 80 °C: I = V / R = 9 / 200 = 0.045 A = 45 mA

As temperature increases, resistance decreases and current increases.

Worked Example 5 — LDR in a Circuit

Question: An LDR is connected in series with a 6 V battery and a lamp. In bright light the LDR has resistance 200 Ω and the lamp has resistance 100 Ω. In darkness the LDR resistance rises to 10 000 Ω. Calculate the total current in each condition.

Solution:

Bright light: Total R = 200 + 100 = 300 Ω. I = 6 / 300 = 0.02 A = 20 mA (lamp is on).

Darkness: Total R = 10 000 + 100 = 10 100 Ω. I = 6 / 10 100 = 0.000594 A = 0.59 mA (lamp is very dim/off).
Worked Example 6 — Explaining I-V Characteristics

Question: Explain why the I-V graph for a filament lamp is curved, not a straight line.

Solution: As the current through the filament lamp increases, the filament gets hotter. The increased vibration of the metal ions in the filament makes it harder for electrons to pass through, so resistance increases. This means that as voltage increases, the current does not increase proportionally — the graph curves and flattens. The filament lamp is not an Ohmic conductor because its resistance changes with temperature.

❓ Practice Questions

Q1: Foundation Name the component that measures current and state how it is connected in a circuit.

Q2: Foundation A resistor has 8 V across it and a current of 2 A flows through it. Calculate its resistance.

Q3: Foundation Describe the difference between the I-V graph of a resistor and a filament lamp.

Q4: Higher A thermistor is connected to a 5 V supply. At 25 °C its resistance is 1000 Ω. At 100 °C its resistance is 100 Ω. Calculate the current at each temperature and explain the difference.

Q5: Higher Explain why a diode only allows current to flow in one direction. How would this appear on an I-V graph?

Q6: Higher A student investigates the I-V characteristics of a resistor. They vary the voltage and measure the current. State one safety precaution and one way to improve accuracy.

✅ Answers

  1. An ammeter measures current. It is connected in series with the component — the current flows through it.
  2. R = V / I = 8 / 2 = 4 Ω.
  3. A resistor (at constant temperature) gives a straight line through the origin — current is directly proportional to voltage (Ohmic). A filament lamp gives a curved graph that flattens at higher voltages — as current increases, the filament heats up and resistance increases, so current increases more slowly (non-Ohmic).
  4. At 25 °C: I = 5 / 1000 = 0.005 A = 5 mA. At 100 °C: I = 5 / 100 = 0.05 A = 50 mA. The current is much higher at 100 °C because the thermistor's resistance decreases as temperature increases (more charge carriers are released), allowing more current to flow.
  5. A diode has very low resistance in the forward direction (allows current through) but very high resistance in the reverse direction (blocks current). On the I-V graph: there is current in the forward direction (positive voltage), rising steeply once the threshold voltage is exceeded. In the reverse direction (negative voltage), the current is essentially zero.
  6. Safety precaution: do not exceed the maximum voltage rating of the resistor to avoid overheating/burning out. Improving accuracy: take multiple readings and calculate a mean, or use smaller voltage increments to get more data points for a smoother graph.

🎯 Exam Tips

🔬 Required Practical

Required Practical: Investigating I-V Characteristics

Aim: To investigate how the current through a resistor, a filament lamp and a diode varies with the potential difference across each component.

Method: Set up a circuit with a variable power supply, ammeter in series with the component, and voltmeter in parallel across the component. Vary the p.d. from 0 V in small steps (e.g. 0.5 V intervals) and record the current at each voltage. Reverse the power supply connections to obtain negative voltage readings. Repeat for each component. Plot I-V graphs for each component.

Variables: IV: Potential difference across the component, DV: Current through the component, Control: Temperature of the component (allow to cool between readings), same circuit setup

🔢 Maths Skills

Mathematical Skills

You must be able to rearrange V = IR to find any unknown quantity. Remember: V = I × R, I = V ÷ R, R = V ÷ I. Always check units — current in amps, voltage in volts, resistance in ohms. Convert mA to A by dividing by 1000.
Maths Example

A component has a resistance of 470 Ω and a current of 52 mA flows through it. Calculate the voltage.
I = 52 mA = 0.052 A
V = I × R = 0.052 × 470 = 24.44 V ≈ 24 V

⚠️ Common Misconceptions

Watch Out!

1. Wrong: Current is "used up" as it goes around a circuit Correct: Current is the same everywhere in a series circuit — energy is transferred, not charge

2. Wrong: Voltage flows through a circuit Correct: Current flows; voltage (potential difference) is measured across a component — it is the energy per unit charge

3. Wrong: Resistance is "bad" and wastes energy Correct: Resistance is a property that opposes current; it is essential — without resistance, current would be dangerously high

4. Wrong: Higher resistance means less energy is transferred Correct: Higher resistance means less current flows for a given voltage; the energy transferred per unit charge (V) is set by the supply

✍️ 6-Mark Question

Extended Answer

6 marks: Compare the I-V characteristics of a resistor, a filament lamp and a diode. Include descriptions of the graph shapes and explanations for each.

A resistor at constant temperature is an Ohmic conductor. Its I-V graph is a straight line through the origin, meaning current is directly proportional to voltage. The resistance remains constant. A filament lamp is a non-Ohmic conductor. Its I-V graph is a curve that flattens at higher voltages. As current increases, the filament heats up, the metal ions vibrate more, and resistance increases, so current increases less quickly. A diode only allows current to flow in the forward direction (forward bias). On the I-V graph, current is zero in reverse bias and rises steeply once the threshold voltage (~0.6 V) is exceeded in forward bias. The diode has very high resistance in reverse and very low resistance in forward bias above the threshold.

Mark scheme: 1 mark — resistor straight line / Ohmic, 1 mark — resistance constant, 1 mark — lamp curves / non-Ohmic, 1 mark — resistance increases with temperature, 1 mark — diode conducts in one direction only, 1 mark — reference to threshold voltage or very high reverse resistance

📊 AO3: Analyse & Evaluate

Analysis and Evaluation

A student investigates the I-V characteristics of a component and records the following data:

Voltage (V)0123456
Current (A)00.100.180.240.280.300.31

(a) Plot a sketch of the I-V graph and state whether the component is Ohmic or non-Ohmic. Justify your answer.

(b) Calculate the resistance of the component at 1 V and at 6 V. Explain why the resistance changes.

(c) The student did not allow the component to cool between readings. Explain how this affects the validity of the results and suggest an improvement.

Answers: (a) The graph curves and flattens — the component is non-Ohmic because current is not proportional to voltage. (b) At 1 V: R = 1/0.10 = 10 Ω. At 6 V: R = 6/0.31 = 19.4 Ω. Resistance increases because the component heats up (it is a filament lamp). (c) Not allowing cooling means temperature is an uncontrolled variable, reducing validity. Improvement: switch off the supply between readings and allow the component to return to room temperature, or use smaller voltage increments to minimise heating.

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