R2: Scale Drawings
Use scale factors, scale diagrams and maps
Use scale factors, scale diagrams and maps
| Scale | Meaning | Use |
|---|---|---|
| 1 : 100 | 1 cm represents 100 cm (1 m) | House plans |
| 1 : 1000 | 1 cm represents 1000 cm (10 m) | Site plans |
| 1 : 25000 | 1 cm represents 250 m | OS Maps |
| 1 : 50000 | 1 cm represents 500 m | OS Maps |
A map has a scale of 1 : 25000. A distance on the map measures 4 cm. What is the real distance?
Solution:
Real distance = 4 × 25000 = 100000 cm
Convert to km: 100000 ÷ 100000 = 1 km
Or: 4 × 250 m = 1000 m = 1 km
A scale drawing uses a scale of 1 : 20. A wall in real life is 3.5 m long. How long is it on the drawing?
Solution:
Convert: 3.5 m = 350 cm
Drawing length = 350 ÷ 20 = 17.5 cm
A rectangle has sides 4 cm and 6 cm. It is enlarged by a scale factor of 3. What are the new dimensions?
Solution:
New sides = 4 × 3 = 12 cm and 6 × 3 = 18 cm
A shape has been enlarged from a scale factor of 1 : 5. If the original side was 8 cm, what is the new length?
Solution:
New length = 8 × 5 = 40 cm
On a 1 : 50000 map, two towns are 6.4 cm apart. Calculate the actual distance in kilometres.
Solution:
Actual distance = 6.4 × 50000 = 320000 cm
Convert: 320000 ÷ 100000 = 3.2 km
Quick method: 6.4 × 0.5 km = 3.2 km
A road is 15 km long. How long will it appear on a 1 : 100000 map?
Solution:
Convert: 15 km = 1500000 cm
Map length = 1500000 ÷ 100000 = 15 cm
A garden plan at 1 : 100 shows an area of 25 cm². What is the actual area?
Solution:
Length scale factor = 100
Area scale factor = 100² = 10000
Actual area = 25 × 10000 = 250000 cm² = 25 m²
Q1: A map has scale 1 : 50000. A distance measures 8 cm. What is the real distance in km?
Q2: A drawing uses scale 1 : 40. A table is 1.8 m long in real life. How long is it on the drawing?
Q3: A shape with sides 3 cm and 5 cm is enlarged by scale factor 4. Find the new dimensions.
Q4: Two villages are 7.5 km apart. How far apart are they on a 1 : 25000 map?
Q5: A model car has scale 1 : 24. If the model is 18 cm long, how long is the real car?
A map has scale 1:25,000. Two towns are 14.4 cm apart on the map. A road is being built that will reduce the actual distance by 6 km. How far apart will the towns appear on a new map with the same scale?
Actual distance = 14.4 × 25,000 = 360,000 cm = 3.6 km. New actual distance = 3.6 − 6 = negative — this is impossible! Check: 14.4 × 25,000 = 360,000 cm = 3.6 km, so reducing by 6 km is not possible for this pair. The question needs checking. If the reduction were 2 km: new distance = 1.6 km = 160,000 cm. New map distance = 160,000 ÷ 25,000 = 6.4 cm.
1. Wrong: Scale 1:50,000 means 1 cm = 50,000 km Correct: 1 cm = 50,000 cm = 0.5 km
2. Wrong: Measuring bearings anti-clockwise from North Correct: Bearings are always measured clockwise from North
3. Wrong: Forgetting to convert map distance to actual distance before calculating Correct: Always multiply by the scale factor first
6 marks: A scale drawing of a field is shown with scale 1:2000. The field on the drawing measures 8.5 cm by 6.2 cm. A path of width 2 m runs diagonally across the actual field. Calculate the area of the field excluding the path. Give your answer in m².
Actual length = 8.5 × 2000 = 17,000 cm = 170 m. Actual width = 6.2 × 2000 = 12,400 cm = 124 m. Total field area = 170 × 124 = 21,080 m². Diagonal = √(170² + 124²) = √(28900 + 15376) = √44276 ≈ 210.4 m. Path area = 210.4 × 2 = 420.8 m². Field area excluding path = 21,080 − 420.8 = 20,659.2 m².
Mark scheme: M1 scale conversion, A1 actual dimensions, M1 area formula, A1 total area, M1 diagonal/path calculation, A1 final area
A student draws two points A and B on a map (scale 1:10,000) and measures the distance as 7.2 cm. They then measure the bearing of B from A as 045°.
(a) Calculate the actual distance between A and B in kilometres.
(b) The student's ruler has a precision of ±0.1 cm. What is the range of possible actual distances?
(c) Is it possible to use scale drawings to find exact distances in real life? Explain your answer.
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