ST14: Measures of Central Tendency
Learn how to calculate and interpret mode, median, mean, weighted mean, and geometric mean, and how to choose the most appropriate average for GCSE Statistics.
Learn how to calculate and interpret mode, median, mean, weighted mean, and geometric mean, and how to choose the most appropriate average for GCSE Statistics.
Learn how to calculate and interpret mode, median, mean, weighted mean, and geometric mean, and how to choose the most appropriate average for GCSE Statistics.
For Measures of Central Tendency, you must know:
Q: Find the mode, median, and mean of: 3, 5, 5, 7, 10
Q: A student scores 65, 70, and 75 in tests weighted 2, 3, and 5 respectively. Calculate the weighted mean.
Q: An investment grows by 10% in year 1 and 20% in year 2. Why is the geometric mean more appropriate than the arithmetic mean for the average growth rate?
Q: A dataset has values 2, 3, 3, 3, 100. Explain why the median is more appropriate than the mean.
Q: From a grouped frequency table with total frequency 50 and Σ(f × midpoint) = 1200, find the estimated mean.
✗ Finding the median by just picking the middle number without ordering the data first ✓ Data must be arranged in ascending order before finding the median; the median position is (n + 1) ÷ 2 for n values.
✗ Using the arithmetic mean for average percentage growth rates ✓ Use the geometric mean for multiplicative data like growth rates; the arithmetic mean overestimates the true average growth.
✗ Calculating the mean of a grouped frequency table using class boundaries instead of midpoints ✓ Use the midpoint of each class interval (average of lower and upper boundaries) to estimate the mean, not the boundary values.
✗ Choosing the mean when the data is heavily skewed or has outliers without justification ✓ If data is skewed or has outliers, the median is usually more representative; the mean is pulled towards the extreme values.
The table shows the number of siblings for 30 students. Calculate the estimated mean. 0–1: frequency 8, 2–3: frequency 14, 4–5: frequency 6, 6–7: frequency 2
Find midpoints and calculate f × midpoint: Class | Midpoint (m) | f | f × m 0–1 | 0.5 | 8 | 4 2–3 | 2.5 |14 | 35 4–5 | 4.5 | 6 | 27 6–7 | 6.5 | 2 | 13 Total | |30 | 79 Estimated mean = Σ(f × m) ÷ Σf = 79 ÷ 30 = 2.63 (to 2 d.p.) This is an estimate because we have used midpoints rather than the actual data values within each class.
AO1 (Knowledge & Understanding): Demonstrate knowledge and understanding of measures of central tendency, including data collection, presentation and calculation techniques relevant to Edexcel 1ST0 & AQA 8382.
AO2 (Application): Apply knowledge and understanding of measures of central tendency to interpret data, reason statistically and draw conclusions in context.
AO3 (Evaluation): Evaluate statistical methods and conclusions, assessing appropriateness, reliability, validity and bias through the statistical enquiry cycle.
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