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Algebraic Expressions
Exam Board: AQA Pearson Edexcel OCR WJEC / Eduqas CCEA
π Key Points
Key Fact: Collecting like terms: only terms with identical variables and powers can be combined
Key Fact: Expanding brackets: multiply each term inside by the term outside (FOIL for double brackets)
Key Fact: Difference of two squares: a^2 - b^2 = (a + b)(a - b)
Key Fact: Perfect square trinomials: a^2 +/- 2ab + b^2 = (a +/- b)^2
Key Fact: Factorising by grouping: pair terms to extract common factors
Key Fact: Algebraic fractions: factorise numerator and denominator first, then cancel common factors
Key Fact: Index laws: xα΅ x xα΅ = xα΅βΊα΅, xα΅ Γ· xα΅ = xα΅β»α΅, (xα΅)α΅ = xα΅α΅, xβ° = 1, xβ»α΅ = 1/xα΅
Key Fact: Polynomial long division: dividend = divisor x quotient + remainder
Key Fact: Factor theorem: if f(a) = 0 then (x - a) is a factor of f(x)
π― Learning Objectives
Simplify algebraic expressions by collecting like terms Expand single and double brackets using distributive law Factorise quadratic expressions including difference of two squares Manipulate algebraic fractions with numerical and algebraic denominators Apply index laws to simplify expressions with powers Use the factor theorem and remainder theorem for polynomial division
π‘ Worked Example
Exam-Style Question
Question: Simplify fully: (2x^2 + 3x - 2)/(x + 2) - (x^2 - 4)/(x - 2)
Model Answer:
Factorise: (2x-1)(x+2)/(x+2) - (x-2)(x+2)/(x-2) = (2x-1) - (x+2) = x - 3
β Practice Questions
Questions:
Expand and simplify (3x - 2)(x + 4) - (x - 1)^2 Factorise completely: 6x^2 + 13x + 6 Simplify: (x^3 - 8)/(x^2 - 4) Divide 2x^3 - 5x^2 + 3x - 1 by (x - 2) using polynomial division Given f(x) = x^3 - 6x^2 + 11x - 6, show (x-1) is a factor and factorise fully Simplify: (2x^2yβ»^3)^3 Γ· (4xβ»ΒΉy^2)^2
π Past Papers & Exam Resources
π Further Reading & Resources
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Quadratic Equations β