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A7: Functions

Higher Only AQAEdexcelOCREduqasCCEA

Work with functions and their inverses; composite functions; f(x), fg(x), f⁻¹(x) notation

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📋 Key Concepts

Function: A rule that takes an input (x) and gives exactly one output. Written as f(x), g(x), etc.
Notation:
f(x) means "function f of x"
f(3) means "substitute x = 3 into function f"
Key terms:
  • Domain: All possible input values
  • Range: All possible output values

📝 Evaluating Functions

Example 1

Given f(x) = 3x - 2, find:

a) f(4)

b) f(-2)

c) f(a)

Solution:

a) f(4) = 3(4) - 2 = 12 - 2 = 10

b) f(-2) = 3(-2) - 2 = -6 - 2 = -8

c) f(a) = 3a - 2

Example 2

Given g(x) = x² + 1, find:

a) g(3)

b) g(-3)

c) g(2x)

Solution:

a) g(3) = 3² + 1 = 10

b) g(-3) = (-3)² + 1 = 10

c) g(2x) = (2x)² + 1 = 4x² + 1

📝 Inverse Functions

Inverse function f⁻¹(x): The function that "undoes" f. If f(a) = b, then f⁻¹(b) = a.
Method to find f⁻¹(x):
  1. Write y = f(x)
  2. Make x the subject
  3. Replace y with x
Example 3

Find f⁻¹(x) when f(x) = 3x + 5

Solution:

Step 1: Let y = 3x + 5

Step 2: Make x the subject:

y - 5 = 3x

x = y - 53

Step 3: Replace y with x:

f⁻¹(x) = x - 53

Example 4

Find f⁻¹(x) when f(x) = x + 32

Solution:

y = x + 32

2y = x + 3

x = 2y - 3

f⁻¹(x) = 2x - 3

📝 Composite Functions

Composite function fg(x): Apply g first, then apply f to the result. fg(x) = f(g(x))
Order matters: fg(x) ≠ gf(x) in general. Always work from the inside out.
Example 5

Given f(x) = 2x + 1 and g(x) = x², find:

a) fg(3)

b) gf(3)

Solution:

a) fg(3) = f(g(3)) = f(3²) = f(9) = 2(9) + 1 = 19

b) gf(3) = g(f(3)) = g(2(3) + 1) = g(7) = 7² = 49

Example 6

Given f(x) = x + 4 and g(x) = 2x - 1, find fg(x)

Solution:

fg(x) = f(g(x))

= f(2x - 1)

= (2x - 1) + 4

= 2x + 3

Example 7

Given f(x) = 3x and g(x) = x - 2, find gf(x)

Solution:

gf(x) = g(f(x))

= g(3x)

= 3x - 2

📝 Harder Inverse Functions

Example 8

Find f⁻¹(x) when f(x) = x² + 5, x ≥ 0

Solution:

y = x² + 5

y - 5 = x²

x = √(y - 5)

f⁻¹(x) = √(x - 5), x ≥ 5

❓ Practice Questions

Q1: Given f(x) = 4x - 3, find f(5) and f(-2).

Q2: Given g(x) = x² - 1, find g(3) and g(x + 1).

Q3: Find the inverse of f(x) = 2x - 7.

Q4: Find the inverse of g(x) = x4 + 1.

Q5: Given f(x) = x + 3 and g(x) = 2x, find fg(x) and gf(x).

Q6: Given f(x) = x² and g(x) = x + 1, find fg(2) and gf(2).

✅ Answers

  1. f(5) = 17, f(-2) = -11
  2. g(3) = 8, g(x + 1) = (x + 1)² - 1 = x² + 2x
  3. f⁻¹(x) = x + 72
  4. g⁻¹(x) = 4(x - 1) = 4x - 4
  5. fg(x) = 2x + 3, gf(x) = 2(x + 3) = 2x + 6
  6. fg(2) = f(g(2)) = f(3) = 9, gf(2) = g(f(2)) = g(4) = 5

🎯 Exam Tips

🧠 Problem-Solving Strategies

Problem-Solving

For composite functions, always work from the inside out. For inverse functions, swap x and y then make y the subject. Verify inverses by checking f(f⁻¹(x)) = x. Pay close attention to order — fg(x) means apply g first.
Multi-Step Problem

Given f(x) = 2x + 1 and g(x) = x². (a) Find ff(3). (b) Find f⁻¹(x). (c) Solve fg(x) = 33.

Solution:

(a) f(3) = 7, then f(7) = 15

(b) y = 2x + 1 → x = y - 12, so f⁻¹(x) = x - 12

(c) fg(x) = f(x²) = 2x² + 1 = 33 → 2x² = 32 → x² = 16 → x = ±4

⚠️ Common Errors

Watch Out!

1. Wrong: fg(x) means f × g(x) Correct: fg(x) = f(g(x)) — apply g first, then f to the result

2. Wrong: f⁻¹(x) means 1f(x) Correct: f⁻¹(x) is the inverse function, not the reciprocal

3. Wrong: fg(x) = gf(x) always Correct: Order matters! fg(x) ≠ gf(x) in general

✍️ 6-Mark Exam Question

Extended Answer

6 marks: f(x) = 3x - 5 and g(x) = x + 24. (a) Find f⁻¹(x). (b) Find gf(3). (c) Show that fg(x) ≠ gf(x) by finding both expressions.

(a) y = 3x - 5 → y + 5 = 3x → x = y + 53, so f⁻¹(x) = x + 53

(b) f(3) = 3(3) - 5 = 4. g(4) = 4 + 24 = 64 = 1.5

(c) fg(x) = f(x + 24) = 3(x + 24) - 5 = 3x + 64 - 5 = 3x - 144

gf(x) = g(3x - 5) = 3x - 5 + 24 = 3x - 34

These are different: 3x - 1443x - 34

Mark scheme: (a) 2 marks. (b) 1 mark for f(3), 1 mark for final answer. (c) 1 mark for fg(x), 1 mark for gf(x).

📊 AO3: Reason & Interpret

Reasoning and Interpretation

f(x) = 2x + 3 converts a temperature from °C to an adjusted scale. g(x) = x - 32 is its inverse.

(a) What does f(0) represent?

(b) If the output of f is 15, what was the input?

(c) Explain why g undoes f.

Answers: (a) f(0) = 3 — the adjusted value when the input is 0°C. (b) f⁻¹(15) = 15 - 32 = 6. (c) gf(x) = g(2x+3) = 2x+3-32 = x. So applying g after f returns the original value.

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