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A4: Simplifying Expressions

Foundation Higher AQAEdexcelOCREduqasCCEA

Simplify and manipulate algebraic expressions: collecting like terms, expanding brackets, factorising

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📋 Key Concepts

Simplifying: Writing expressions in their simplest form by combining like terms and removing unnecessary brackets.
Key Skills:
  • Collecting like terms
  • Expanding brackets
  • Factorising expressions

📝 Collecting Like Terms

Like terms: Terms with the same variable(s) and same powers. Only like terms can be combined.
Example 1

Which are like terms?

a) 3x and 5x → Yes (both have x)

b) 2x² and 3x → No (different powers)

c) 4ab and 7ab → Yes (both have ab)

d) 2xy and 3yx → Yes (same variables, order doesn't matter)

Example 2

Simplify: 3x + 2x + 5x

Solution: 3x + 2x + 5x = 10x

Add the coefficients: 3 + 2 + 5 = 10

Example 3

Simplify: 4a + 3b - 2a + 5b

Solution:

Collect a terms: 4a - 2a = 2a

Collect b terms: 3b + 5b = 8b

Answer: 2a + 8b

Example 4

Simplify: 5x² + 2x - 3x² + 7

Solution:

x² terms: 5x² - 3x² = 2x²

x terms: 2x

Constants: 7

Answer: 2x² + 2x + 7

📝 Expanding Single Brackets

Rule: Multiply the term outside the bracket by each term inside the bracket.
a(b + c) = ab + ac
a(b - c) = ab - ac
Example 5

Expand: 3(x + 4)

Solution: 3(x + 4) = 3 × x + 3 × 4 = 3x + 12

Example 6

Expand: 2(5a - 3)

Solution: 2(5a - 3) = 2 × 5a - 2 × 3 = 10a - 6

Example 7

Expand: -2(x + 5)

Solution: -2(x + 5) = -2x - 10

Be careful with negative signs!

📝 Expanding Double Brackets

FOIL method: First, Outer, Inner, Last
Example 8

Expand: (x + 3)(x + 2)

Solution using FOIL:

First: x × x = x²

Outer: x × 2 = 2x

Inner: 3 × x = 3x

Last: 3 × 2 = 6

Add together: x² + 2x + 3x + 6 = x² + 5x + 6

Example 9

Expand: (2x - 1)(x + 4)

Solution:

First: 2x × x = 2x²

Outer: 2x × 4 = 8x

Inner: -1 × x = -x

Last: -1 × 4 = -4

Answer: 2x² + 8x - x - 4 = 2x² + 7x - 4

📝 Factorising

Factorising: The reverse of expanding. Find the highest common factor (HCF) and put it outside brackets.
Example 10

Factorise: 6x + 9

Solution:

HCF of 6 and 9 is 3

6x ÷ 3 = 2x

9 ÷ 3 = 3

Answer: 3(2x + 3)

Example 11

Factorise: 4x² - 8x

Solution:

HCF of 4x² and 8x is 4x

4x² ÷ 4x = x

-8x ÷ 4x = -2

Answer: 4x(x - 2)

Example 12

Factorise: 3x² + 12x

Solution:

HCF of 3x² and 12x is 3x

Answer: 3x(x + 4)

🧮 Worked Examples — Exam Style

Simplifying expressions is the grammar of algebra — every later topic assumes it. Two skills: collecting like terms (only identical letter parts combine) and expanding brackets (everything inside is multiplied).

Expand and simplify: 3(2x + 5) − 2(x − 4)

Expand each bracket: 6x + 15 − 2x + 8

Careful with the second: −2 × (−4) = +8

Collect: (6x − 2x) + (15 + 8) = 4x + 23

M1 for both expansions, A1 for 4x + 23. The minus-before-bracket case is the single most examined slip.

Factorise fully: 6x² + 9x

Highest common factor of 6x² and 9x is 3x.

6x² ÷ 3x = 2x  and  9x ÷ 3x = 3

Answer: 3x(2x + 3)

M1 for 3x, A1 for 3x(2x + 3). 'Fully' means take out ALL common factors — 3(2x² + 3x) loses the mark.

Exam wording to expect: "Simplify", "Expand and simplify", "Factorise fully".

❓ Practice Questions

Q1: Simplify: 5a + 3a - 2a

Q2: Simplify: 4x + 3y - 2x + 5y

Q3: Expand: 4(x - 3)

Q4: Expand and simplify: (x + 2)(x + 5)

Q5: Factorise: 8x + 12

Q6: Factorise: 5x² - 15x

Q7: Expand and simplify: 3(2x − 1) − 2(x + 4)

Q8: Factorise fully: 10x² − 5x

✅ Answers

  1. 6a
  2. 2x + 8y
  3. 4x - 12
  4. x² + 7x + 10
  5. 4(2x + 3)
  6. 5x(x - 3)

🧮 Worked Examples — Harder Exam Style

Expand and simplify: (2x + 3)(x − 4)

Multiply every term in the first bracket by every term in the second:

2x × x = 2x²  ·  2x × (−4) = −8x  ·  3 × x = 3x  ·  3 × (−4) = −12

Combine: 2x² − 8x + 3x − 12 = 2x² − 5x − 12

M1 for three correct products, A1 for 2x² − 5x − 12. Check with x = 1: LHS (5)(−3) = −15; RHS 2 − 5 − 12 = −15 ✓

📋 Model Answers — Full Working

Every mark comes from the working, not just the answer. These model answers show the lines a mark scheme expects to see.

Q1. All three terms are a-terms: 5 + 3 − 2 = 6 → 6a

Q2. x-terms: 4 − 2 = 2x; y-terms: 3 + 5 = 8y → 2x + 8y. Unlike terms never combine — 2x + 8y is finished.

Q3. 4 × x and 4 × (−3): 4x − 12

Q4. FOIL: x² + 5x + 2x + 10 = x² + 7x + 10

Q5. HCF of 8 and 12 is 4 → 4(2x + 3)

Q6. HCF is 5x: 5x² ÷ 5x = x, 15x ÷ 5x = 3 → 5x(x − 3)

Q7. 6x − 3 − 2x − 8 = 4x − 11 (the −2 multiplies BOTH terms: −2 × +4 = −8)

Q8. HCF 5x → 5x(2x − 1)

📌 Key Facts to Memorise

🗺️ In the Exam

Simplifying sits inside almost every algebra question as a first step: solving equations, expanding for quadratics, substitution. Standalone questions are 1–3 marks on Paper 1 (non-calculator).

Links to: solving equations (A17), quadratic graphs (A11), factorising quadratics (A18).

🧭 Board Focus — AQA

Spec 8300. Three papers, each 80 marks and 1h30: Paper 1 non-calculator, Papers 2 and 3 calculator. Foundation/Higher tiers. Roughly a third of the marks sit under AO2 (reasoning) and AO3 (problem-solving), so show every line of working — method marks survive arithmetic slips.

Always check: specification details change — confirm paper structure and set texts against the current specification for your exam year.

🎯 Exam Tips

🧠 Problem-Solving Strategies

Problem-Solving

When simplifying, organise your work: collect like terms systematically, handle signs carefully when expanding, and always check factorising by expanding back. For double brackets, use FOIL or a grid method to ensure no terms are missed.
Multi-Step Problem

A garden has length (x + 3) metres and width (x + 1) metres. A path of width 1 metre surrounds it. Find an expression for the area of the path.

Solution:

Step 1: Garden area = (x + 3)(x + 1) = x² + 4x + 3

Step 2: Total area including path = (x + 5)(x + 3) = x² + 8x + 15

Step 3: Path area = Total - Garden = (x² + 8x + 15) - (x² + 4x + 3) = 4x + 12 m²

⚠️ Common Errors

Watch Out!

1. Wrong: 3x + 5x = 8x² Correct: 3x + 5x = 8x (add coefficients, don't change the variable part)

2. Wrong: -2(x - 3) = -2x - 6 Correct: -2(x - 3) = -2x + 6 (negative × negative = positive)

3. Wrong: Factorising 6x + 9 as 3(2x + 3) then writing 6x + 9 = 3(2x + 9) Correct: 6x + 9 = 3(2x + 3) — check: 3 × 2x = 6x, 3 × 3 = 9 ✓

✍️ 6-Mark Exam Question

Extended Answer

6 marks: (a) Expand and simplify (2x + 3)(x - 5). (b) Hence or otherwise, expand and simplify (2x + 3)(x - 5)(x + 1). (c) Factorise 4x² - 12x fully.

(a) (2x + 3)(x - 5) = 2x² - 10x + 3x - 15 = 2x² - 7x - 15

(b) (2x² - 7x - 15)(x + 1) = 2x³ + 2x² - 7x² - 7x - 15x - 15 = 2x³ - 5x² - 22x - 15

(c) 4x² - 12x = 4x(x - 3)

Mark scheme: (a) 2 marks for correct expansion and simplification. (b) 2 marks for multiplying correctly. (c) 2 marks for fully factorised (both 4 and x outside).

📊 AO3: Reason & Interpret

Reasoning and Interpretation

The area of a rectangle is (x + 4)(2x - 1) cm².

(a) Expand to find the area expression.

(b) If x = 5, what is the area?

(c) Explain why x must be greater than 0.5 for the expression to make sense.

Answers: (a) 2x² - x + 8x - 4 = 2x² + 7x - 4 cm². (b) 2(25) + 7(5) - 4 = 50 + 35 - 4 = 81 cm². (c) If x ≤ 0.5, then (2x - 1) ≤ 0, giving a negative width which is impossible.

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