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A5: Rearranging Formulae

Foundation Higher AQAEdexcelOCREduqasCCEA

Use standard mathematical formulae; rearrange formulae to change the subject

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📋 Key Concepts

Subject of a formula: The variable that is on its own on one side of the equals sign.
Changing the subject: Rearrange the formula to make a different variable the subject.
Example: In A = lb, A is the subject
We can rearrange to make l the subject: l = A⁄b

📝 Basic Rearranging

Method: Use inverse operations to isolate the new subject. Do the same to both sides.
Example 1

Rearrange v = u + at to make t the subject.

Solution:

Step 1: Subtract u from both sides: v - u = at

Step 2: Divide both sides by a: v - u⁄a = t

Answer: t = v - u⁄a

Example 2

Rearrange A = πr² to make r the subject.

Solution:

Step 1: Divide both sides by π: A⁄π = r²

Step 2: Take the square root: √(A⁄π) = r

Answer: r = √(A⁄π)

📝 Rearranging with Multiplication

Rule: If the new subject is multiplied by something, divide both sides by that factor.
Example 3

Rearrange A = lb to make b the subject.

Solution:

Divide both sides by l: A⁄l = b

Answer: b = A⁄l

Example 4

Rearrange s = d⁄t to make d the subject.

Solution:

Multiply both sides by t: st = d

Answer: d = st

📝 Rearranging with Addition/Subtraction

Rule: If something is added to the new subject, subtract it from both sides.
Example 5

Rearrange y = mx + c to make x the subject.

Solution:

Step 1: Subtract c from both sides: y - c = mx

Step 2: Divide both sides by m: y - c⁄m = x

Answer: x = y - c⁄m

📝 Rearranging with Powers

Rule: If the new subject is squared, take the square root. If it's inside a square root, square both sides.
Example 6

Rearrange A = ½bh to make h the subject.

Solution:

Step 1: Multiply both sides by 2: 2A = bh

Step 2: Divide both sides by b: 2A⁄b = h

Answer: h = 2A⁄b

Example 7

Rearrange E = ½mv² to make v the subject.

Solution:

Step 1: Multiply both sides by 2: 2E = mv²

Step 2: Divide both sides by m: 2E⁄m = v²

Step 3: Take square root: v = √(2E⁄m)

📝 Rearranging with the Variable in Two Places

Rule: Collect all terms with the new subject on one side, then factorise.
Example 8

Rearrange ax + b = cx + d to make x the subject.

Solution:

Step 1: Subtract cx from both sides: ax - cx + b = d

Step 2: Subtract b from both sides: ax - cx = d - b

Step 3: Factorise left side: x(a - c) = d - b

Step 4: Divide by (a - c): x = d - b⁄a - c

🧮 Worked Examples — Exam Style

Rearranging = solving an equation where the 'answer' is a letter. Reverse the operations acting on the target letter, one layer at a time.

Rearrange T = 5c + 8 to make c the subject.

Subtract 8: T − 8 = 5c  →  Divide by 5: c = (T − 8)/5

M1 for subtracting 8 first, A1 for the division. Undo in reverse order: +8 was LAST, so it comes off FIRST.

Rearrange V = πr²h to make r the subject.

÷ πh: V/(πh) = r²  →  Square root: r = √(V/(πh))

M1 for dividing by πh, A1 for the root. The root undoes the SQUARE — last-in-first-out again.

Exam wording to expect: "Make … the subject", "Rearrange … to give an equation for …".

❓ Practice Questions

Q1: Rearrange a = 3b + 2 to make b the subject.

Q2: Rearrange F = ma to make a the subject.

Q3: Rearrange C = 2πr to make r the subject.

Q4: Rearrange v² = u² + 2as to make s the subject.

Q5: Rearrange P = 2(l + w) to make w the subject.

Q6: Rearrange ax - 3 = bx + 5 to make x the subject.

Q7: Rearrange y = 4(x − 3) to make x the subject

Q8: Rearrange A = 2(lw + wh) to make w the subject

✅ Answers

  1. b = a - 2⁄3
  2. a = F⁄m
  3. r = C⁄2π
  4. s = v² - u²⁄2a
  5. w = P⁄2 - l
  6. x = 8⁄a - b

🧮 Worked Examples — Harder Exam Style

The formula for converting Celsius to Fahrenheit is F = 1.8C + 32. Rearrange to make C the subject, then convert 95°F to Celsius.

Subtract 32: F − 32 = 1.8C  →  Divide by 1.8: C = (F − 32)/1.8

95°F: C = (95 − 32)/1.8 = 63/1.8 = 35°C

M1 for the rearrangement, A1 for C = (F − 32)/1.8, A1 for 35°C. Applied rearrangements (conversion, physics) are the standard exam context.

📋 Model Answers — Full Working

Every mark comes from the working, not just the answer. These model answers show the lines a mark scheme expects to see.

Q1. a − 2 = 3b → b = (a − 2)/3

Q2. Divide by m: a = F/m

Q3. Divide by 2π: r = C/(2π)

Q4. Subtract u², divide by 2a: s = (v² − u²)/(2a)

Q5. P/2 = l + w → w = P/2 − l

Q6. ax − bx = 8 → x(a − b) = 8 → x = 8/(a − b) — factorise when x appears twice

Q7. y/4 = x − 3 → x = y/4 + 3

Q8. A/(2l) − wh = lw → hmm, divide first: A/2 = lw + wh = w(l + h) → w = A/(2(l + h))

📌 Key Facts to Memorise

🗺️ In the Exam

Rearranging: 2–3 marks on every paper — it is the gateway skill for science formulas, geometry and compound measures. Two-variable targets (Q6 style) mark the grade-5 boundary.

Links to: solving equations (A17), substitution (A2), compound measures (R1).

🧭 Board Focus — AQA

Spec 8300. Three papers, each 80 marks and 1h30: Paper 1 non-calculator, Papers 2 and 3 calculator. Foundation/Higher tiers. Roughly a third of the marks sit under AO2 (reasoning) and AO3 (problem-solving), so show every line of working — method marks survive arithmetic slips.

Always check: specification details change — confirm paper structure and set texts against the current specification for your exam year.

🎯 Exam Tips

🧠 Problem-Solving Strategies

Problem-Solving

Work backwards through BIDMAS to isolate the new subject. Deal with additions/subtractions first, then multiplications/divisions, then powers/roots. If the variable appears twice, collect all terms with it on one side and factorise.
Multi-Step Problem

The kinetic energy formula is E = ½mv². (a) Rearrange to make v the subject. (b) Find v when E = 100 and m = 8.

Solution:

(a) Step 1: 2E = mv². Step 2: v² = 2E⁄m. Step 3: v = √(2E⁄m)

(b) v = √(200⁄8) = √25 = 5 m/s

⚠️ Common Errors

Watch Out!

1. Wrong: Rearranging v = u + at to make t: t = v - u/a Correct: t = v - u⁄a (the whole of v - u is divided by a)

2. Wrong: From A = πr², rearranging to r = A⁄π Correct: r² = A⁄π, so r = √(A⁄π) (don't forget the square root)

3. Wrong: Rearranging ax + b = cx + d by moving ax and d: ax - d = cx Correct: ax - cx = d - b, then factorise: x(a - c) = d - b

✍️ 6-Mark Exam Question

Extended Answer

6 marks: The formula for the surface area of a cylinder (excluding ends) is A = 2πrh. (a) Rearrange to make h the subject. (b) Rearrange to make r the subject. (c) A can has A = 314 cm² and r = 5 cm. Find h. (Use π = 3.14)

(a) h = A⁄2πr

(b) r = A⁄2πh

(c) h = 314⁄2 × 3.14 × 5 = 314⁄31.4 = 10 cm

Mark scheme: (a) 1 mark. (b) 1 mark. (c) 2 marks for substitution, 1 mark for correct answer, 1 mark for units.

📊 AO3: Reason & Interpret

Reasoning and Interpretation

The stopping distance formula is d = v²⁄2a where d = distance, v = initial speed, a = deceleration.

(a) Rearrange to make v the subject.

(b) If a car decelerates at 8 m/s² and stops in 25 m, what was its initial speed?

(c) Explain why doubling the speed more than doubles the stopping distance.

Answers: (a) v = √(2ad). (b) v = √(2 × 8 × 25) = √400 = 20 m/s. (c) Because v is squared in the formula, doubling v gives (2v)² = 4v², so stopping distance is 4 times as large.

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