N12: Fractions & Percentages as Operators
Interpret fractions and percentages as operators
Interpret fractions and percentages as operators
| Fraction | Decimal | Percentage |
|---|---|---|
| 1/2 | 0.5 | 50% |
| 1/4 | 0.25 | 25% |
| 3/4 | 0.75 | 75% |
| 1/5 | 0.2 | 20% |
| 2/5 | 0.4 | 40% |
| 3/5 | 0.6 | 60% |
| 1/8 | 0.125 | 12.5% |
| 1/10 | 0.1 | 10% |
Find 3/4 of £48
Solution:
Step 1: £48 ÷ 4 = £12
Step 2: £12 × 3 = £36
Find 2/5 of 35 kg
Solution:
Step 1: 35 ÷ 5 = 7
Step 2: 7 × 2 = 14 kg
Find 30% of £80
Solution (non-calculator):
10% of £80 = £8
30% = 3 × 10% = 3 × £8 = £24
Find 15% of £240
Solution:
10% of £240 = £24
5% of £240 = £12
15% = £24 + £12 = £36
Find 17% of £600
Solution (calculator):
17% = 0.17
0.17 × 600 = £102
Increase £80 by 25%
Solution:
100% + 25% = 125% = 1.25
£80 × 1.25 = £100
Decrease £150 by 20%
Solution:
100% - 20% = 80% = 0.8
£150 × 0.8 = £120
A TV costs £400. In a sale it has 35% off. Find the sale price.
Solution:
Multiplier for 35% decrease: 1 - 0.35 = 0.65
£400 × 0.65 = £260
Express £18 as a percentage of £72
Solution:
Fraction = 18/72 = 1/4
1/4 × 100 = 25%
In a test, Sarah scored 42 out of 60. What is her percentage?
Solution:
42/60 × 100 = 70%
Percentage change questions chain two operations — and the trap is assuming +20% then −10% returns near the start. Multipliers do the bookkeeping.
A jumper costs £45. The price increases by 20%, then the new price decreases by 10%. What is the final price?
Increase: ×1.20 → £45 × 1.20 = £54
Decrease: ×0.90 → £54 × 0.90 = £48.60
Not £45 × 1.10 — the 10% comes off the NEW price.
M1 for 45 × 1.2, M1 for 54 × 0.9, A1 for £48.60. The net effect is ×1.08 (a rise), not ×1.10.
The value of a car rises from £80 to £92. Write the percentage increase.
Change = 92 − 80 = £12. Percentage = 12 ÷ 80 × 100 = 15%
The rule: change ÷ ORIGINAL × 100 — divide by where you started.
M1 for 12/80, A1 for 15%. Dividing by 92 instead of 80 is the standard slip.
Exam wording to expect: "Find …% of …", "Increase/decrease by …%", "Express … as a percentage of …".
Q1: Find 2/3 of £54
Q2: Find 35% of 240
Q3: Increase £180 by 15%
Q4: Decrease £250 by 30%
Q5: Express 45 as a percentage of 150
Q6: Find 12.5% of 640
Q7: Express 18/45 as a percentage
A phone priced at £240 is discounted by 15% in a sale. The sale price then rises by 15%. Explain why the final price is not £240.
Sale price: 240 × 0.85 = £204
Rise: 204 × 1.15 = £234.60
Why not £240: the 15% rise applies to the SMALLER sale price (£204), so it adds only £30.60, while the discount removed £36. The percentage is of different bases.
M1 for 0.85 and 1.15 multipliers, A1 for £234.60, B1 for the explanation. The explanation line is explicitly asked — 'the percentages are of different amounts' scores.
Every mark in GCSE maths comes from the working, not just the answer. These model answers show the lines a mark scheme expects to see.
Q1. 54 ÷ 3 = 18, then 18 × 2 = £36
Q2. 35% = 0.35 → 0.35 × 240 = 84
Q3. Increase by 15% → multiplier 1.15 → 180 × 1.15 = £207. One multiplication replaces the find-10%-and-add method.
Q4. Decrease by 30% → multiplier 0.70 → 250 × 0.7 = £175
Q5. 45 ÷ 150 × 100 = 30%
Q6. 12.5% = 1/8 → 640 ÷ 8 = 80
Q7. 18/45 = 2/5 (÷9) = 40/100 → 40%
Percentages of amounts: 3–5 marks per paper — VAT, interest, discounts, depreciation. The chained-change version and reverse-percentage appear on Papers 2/3 (calculator).
Links to: fractions of amounts (R3), interest and growth (R9), reverse percentages (Higher R9).
Spec 8300. Three papers, each 80 marks and 1h30: Paper 1 non-calculator, Papers 2 and 3 calculator. Foundation/Higher tiers. Roughly a third of the marks sit under AO2 (reasoning) and AO3 (problem-solving), so show every line of working — method marks survive arithmetic slips.
Always check: specification details change — confirm paper structure and set texts against the current specification for your exam year.
A jacket costs £120. It is reduced by 15% in a sale, then the sale price is reduced by a further 20%. Find the final price and the overall percentage reduction from the original price.
Solution: After 15% off: £120 × 0.85 = £102. After further 20% off: £102 × 0.80 = £81.60. Overall reduction = £120 − £81.60 = £38.40. Overall % = 38.40/120 × 100 = 32%. Note: this is NOT 15% + 20% = 35%.
1. Wrong: A 20% increase then 20% decrease gets back to the original Correct: 100 × 1.2 × 0.8 = 96 — you end up at 96% of the original
2. Wrong: 3/4 of 60 = 60 ÷ 4 × 3 = 45, but 3/4 of 8 = 8 ÷ 3 × 4 Correct: Always divide by denominator first: 8 ÷ 4 × 3 = 6
3. Wrong: Percentage increase from 40 to 50 is 10% (just subtracting) Correct: Increase = 10. Percentage = 10/40 × 100 = 25% (divide by the ORIGINAL)
6 marks: A house was bought for £180,000. After 3 years its value increased by 12%. It was then sold, and the seller paid 1.5% estate agent fees on the sale price. (a) Find the sale price. (b) Find the estate agent fees. (c) Calculate the actual percentage profit the seller made on the original purchase price after fees are deducted.
(a) Sale price = £180,000 × 1.12 = £201,600.
(b) Fees = 1.5% of £201,600 = £201,600 × 0.015 = £3,024.
(c) Profit after fees = £201,600 − £3,024 − £180,000 = £18,576. Percentage profit = 18,576/180,000 × 100 = 10.32%.
Mark scheme: 2 marks for (a), 1 mark for (b), 3 marks for (c) including correct profit calculation and percentage
Shop A has a coat for £160 with "1/3 off" in the sale. Shop B has the same coat for £180 with "40% off".
(a) Which shop offers the cheaper sale price?
(b) How much money would you save by choosing the cheaper option?
(c) Shop A then offers an extra 10% off the already discounted price. Does this make Shop A definitely cheaper than Shop B now? Show working to justify your answer.
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