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G19: Similar Shapes

Higher Only AQAEdexcelOCREduqasCCEA

Compare the areas and volumes of similar shapes; apply relationships between lengths, areas and volumes in similar figures

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📋 Key Concepts

Similar shapes have the same shape but different sizes. All corresponding angles are equal, and corresponding sides are in proportion.
Scale factor: The ratio of corresponding lengths in similar shapes.

📝 Length Scale Factor

Length scale factor (k): The ratio of corresponding lengths.
k = (length in larger shape)/(length in smaller shape)
Example 1

Two similar triangles have corresponding sides 4 cm and 12 cm. Find the scale factor.

Solution:

Scale factor k = 12/4 = 3

The larger triangle is 3 times bigger than the smaller one.

📝 Area Scale Factor

Important: If the length scale factor is k, the area scale factor is k².
Area scale factor = k²
Example 2

Two similar shapes have length ratio 2:5. Find the ratio of their areas.

Solution:

Length scale factor k = 5/2 = 2.5

Area scale factor = k² = 2.5² = 6.25

Area ratio = 1 : 6.25 or 4 : 25

Example 3

A small shape has area 8 cm². A similar larger shape has lengths 3 times bigger. Find the larger area.

Solution:

Area scale factor = 3² = 9

Larger area = 8 × 9 = 72 cm²

📝 Volume Scale Factor

Important: If the length scale factor is k, the volume scale factor is k³.
Volume scale factor = k³
Example 4

Two similar solids have corresponding heights 3 cm and 9 cm. The smaller volume is 20 cm³. Find the larger volume.

Solution:

Length scale factor k = 9/3 = 3

Volume scale factor = 3³ = 27

Larger volume = 20 × 27 = 540 cm³

Example 5

Two similar shapes have volumes in ratio 8:125. Find the ratio of their lengths.

Solution:

Volume ratio = 8 : 125

Length ratio = ∛8 : ∛125 = 2 : 5

Length scale factor = 5/2 = 2.5

📝 Summary Table

Scale FactorLengthAreaVolume
k× k× k²× k³
Working backwards:
  • Area → length: take the square root
  • Volume → length: take the cube root
  • Volume → area: take the cube root, then square

📝 Finding Scale Factors

Example 6

Two similar shapes have areas 12 cm² and 48 cm². Find the length scale factor.

Solution:

Area scale factor = 48/12 = 4

Length scale factor = √4 = 2

Example 7

Two similar solids have volumes 27 cm³ and 216 cm³. Find the ratio of their surface areas.

Solution:

Volume scale factor = 216/27 = 8

Length scale factor = ∛8 = 2

Area scale factor = 2² = 4

Surface area ratio = 1 : 4

❓ Practice Questions

Q1: Two similar shapes have length ratio 4:7. Find the area ratio.

Q2: A shape has area 15 cm². A similar shape has lengths 4 times bigger. Find the larger area.

Q3: Two similar solids have volume ratio 27:64. Find the length ratio.

Q4: Two similar shapes have areas 9 cm² and 144 cm². Find the length scale factor.

Q5: A solid has volume 40 cm³. A similar solid has heights 0.5 times the original. Find the new volume.

✅ Answers

  1. 16 : 49
  2. 15 × 16 = 240 cm²
  3. 3 : 4 (∛27 : ∛64)
  4. √(144/9) = √16 = 4
  5. 40 × 0.5³ = 40 × 0.125 = 5 cm³

🎯 Exam Tips

🧠 Problem-Solving Strategies

Problem-Solving

Similar shapes have equal angles and proportional sides. Linear scale factor = big length / small length. Area scale factor = (linear scale factor) squared. Volume scale factor = (linear scale factor) cubed. To find a length from an area ratio, take the square root. To find a length from a volume ratio, take the cube root.
Multi-Step Problem

Two similar cylinders have heights 4 cm and 10 cm. The smaller has volume 60 cm cubed. Find the volume of the larger cylinder.

Solution: Linear SF = 10/4 = 2.5. Volume SF = 2.5 cubed = 15.625. Larger volume = 60 x 15.625 = 937.5 cm cubed.

⚠️ Common Errors

Watch Out!

1. Wrong: Using the linear scale factor for area: if sides double, area doubles too Correct: If sides double (SF = 2), area multiplies by 2 squared = 4 and volume by 2 cubed = 8.

2. Wrong: Multiplying area by the scale factor instead of squaring the scale factor Correct: Area scales as SF squared. If SF = 3, area multiplies by 9, not 3.

3. Wrong: Confusing similar shapes with congruent shapes Correct: Similar shapes have the same shape but different sizes (SF not 1). Congruent shapes are identical in size and shape (SF = 1).

✍️ 6-Mark Exam Question

Extended Answer

6 marks: Two similar cones have heights 6 cm and 15 cm. The smaller cone has surface area 60 pi cm squared. (a) Find the linear scale factor. (b) Find the surface area of the larger cone. (c) The smaller cone has volume 96 pi cm cubed. Find the volume of the larger cone.

(a) Linear SF = 15/6 = 2.5.

(b) Area SF = 2.5 squared = 6.25. Larger surface area = 60 pi x 6.25 = 375 pi cm squared.

(c) Volume SF = 2.5 cubed = 15.625. Larger volume = 96 pi x 15.625 = 1500 pi cm cubed.

Mark scheme: M1 linear SF, A1 2.5, M1 area SF, A1 375 pi, M1 volume SF, A1 1500 pi

📊 AO3: Reason & Interpret

Reasoning and Interpretation

Two similar rectangles have areas 20 cm squared and 45 cm squared. The smaller has width 4 cm.

(a) Find the width of the larger rectangle.

(b) A student says "The lengths are in the same ratio as the areas." Is this correct?

(c) A third similar rectangle has area 80 cm squared. Find its width.

Answers: (a) Area ratio = 45/20 = 2.25. Linear SF = root 2.25 = 1.5. Larger width = 4 x 1.5 = 6 cm. (b) No — lengths are in the ratio root(area ratio) = 1.5, not the area ratio of 2.25. The student confuses linear and area scaling. (c) Area ratio from small = 80/20 = 4. Linear SF = root 4 = 2. Width = 4 x 2 = 8 cm.

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