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G4: Quadrilaterals & Triangles

Foundation Higher AQAEdexcelOCREduqasCCEA

Apply the properties and definitions of quadrilaterals and triangles

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📋 Key Concepts

Triangles: 3-sided polygons with angles summing to 180°.
Quadrilaterals: 4-sided polygons with angles summing to 360°.

📝 Types of Triangles

TypeSidesAnglesKey Properties
EquilateralAll equalAll 60°3 lines of symmetry
IsoscelesTwo equalTwo equal1 line of symmetry
ScaleneAll differentAll differentNo symmetry
Right-angledAnyOne 90°Pythagoras applies
Example 1

In an isosceles triangle, the equal angles are 68°. Find the third angle.

Solution:

68° + 68° + x = 180°

136° + x = 180°

x = 44°

Example 2

Find the angles in an equilateral triangle.

Solution: All angles are equal. 180° ÷ 3 = 60° each.

📝 Types of Quadrilaterals

Square

  • All sides equal
  • All angles 90°
  • 4 lines of symmetry
  • Diagonals bisect at 90°
  • Diagonals are equal in length

Rectangle

  • Opposite sides equal and parallel
  • All angles 90°
  • 2 lines of symmetry
  • Diagonals are equal in length

Parallelogram

  • Opposite sides equal and parallel
  • Opposite angles equal
  • No lines of symmetry
  • Diagonals bisect each other

Rhombus

  • All sides equal
  • Opposite angles equal
  • 2 lines of symmetry
  • Diagonals bisect at 90°

Trapezium

  • One pair of parallel sides
  • Co-interior angles sum to 180°

Isosceles Trapezium

  • One pair of parallel sides
  • Non-parallel sides equal
  • Base angles equal
  • 1 line of symmetry

Kite

  • Two pairs of adjacent equal sides
  • One pair of equal angles
  • 1 line of symmetry
  • Diagonals intersect at 90°

📝 Comparing Quadrilaterals

PropertySquareRectangleRhombusParallelogram
All sides equal
All angles 90°
Diagonals equal
Diagonals at 90°
Example 3

A parallelogram has angles of 112° and x. Find x.

Solution:

Opposite angles are equal, so one angle is 112°.

Co-interior angles: 112° + x = 180°

x = 68°

Angles are: 112°, 68°, 112°, 68°

❓ Practice Questions

Q1: In an isosceles triangle, the angle between the equal sides is 50°. Find the other two angles.

Q2: How many lines of symmetry does a rhombus have?

Q3: In a kite, one diagonal is 8 cm and the other is 12 cm. At what angle do they intersect?

Q4: A trapezium has parallel sides. If one angle is 72°, what is the angle adjacent to it on the same side?

Q5: Name the quadrilateral with all sides equal but not all angles 90°.

✅ Answers

  1. (180° - 50°) ÷ 2 = 65° each
  2. 2 lines of symmetry
  3. 90° (kite diagonals always intersect at right angles)
  4. 180° - 72° = 108° (co-interior angles)
  5. Rhombus

🎯 Exam Tips

🧠 Problem-Solving Strategies

Problem-Solving

Learn the key properties of each quadrilateral: parallelogram (opposite sides equal and parallel, opposite angles equal), rhombus (all sides equal, diagonals perpendicular), rectangle (all angles 90°, diagonals equal), kite (two pairs of adjacent sides equal, one pair of opposite angles equal). Use these properties to find missing angles and sides.
Multi-Step Problem

In a parallelogram ABCD, ∠A = (4x − 10)° and ∠B = (2x + 30)°. Find all four angles.

Solution: Adjacent angles in a parallelogram sum to 180°. 4x − 10 + 2x + 30 = 180. 6x + 20 = 180. x = 26⅔. ∠A = 4(26⅔) − 10 = 96⅔°. ∠B = 2(26⅔) + 30 = 83⅓°. ∠C = ∠A = 96⅔°, ∠D = ∠B = 83⅓°. Check: 96⅔ + 83⅓ = 180° ✓

⚠️ Common Errors

Watch Out!

1. Wrong: Saying a rhombus has all angles equal (like a square) Correct: A rhombus has all SIDES equal, but only opposite angles are equal. A square is a special rhombus with all angles 90°.

2. Wrong: Thinking a kite has two pairs of parallel sides Correct: A kite has NO parallel sides. It has two pairs of adjacent (next to each other) equal sides, not opposite equal sides.

3. Wrong: Assuming all quadrilaterals have diagonals that bisect each other Correct: Only parallelograms (including rectangles, rhombuses and squares) have bisecting diagonals. A kite and a general trapezium do not.

✍️ 6-Mark Exam Question

Extended Answer

6 marks: ABCD is a rhombus with diagonals AC = 10 cm and BD = 8 cm. (a) Find the length of each side of the rhombus. (b) Find the area of the rhombus. (c) One angle of the rhombus is θ. Find θ to the nearest degree.

(a) The diagonals of a rhombus bisect each other at right angles. Half-diagonals: 5 cm and 4 cm. Side = √(5² + 4²) = √41 ≈ 6.4 cm.

(b) Area = ½ × d₁ × d₂ = ½ × 10 × 8 = 40 cm².

(c) In the right-angled triangle with legs 5 and 4: tan θ = 5/4 (or 4/5 depending on which angle). θ = tan⁻¹(5/4) ≈ 51° and the other angle = 180 − 51 ≈ 129°. The acute angle is approximately 51° and the obtuse angle is approximately 129°.

Mark scheme: M1 halving diagonals, A1 side ≈ 6.4cm, M1 area formula, A1 40cm², M1 trig, A1 angles

📊 AO3: Reason & Interpret

Reasoning and Interpretation

A student says: "All squares are rectangles, and all rectangles are parallelograms, so all squares are parallelograms."

(a) Is the conclusion logically valid?

(b) Give two additional properties a square has that a general parallelogram does not.

(c) Is every rhombus a square? Explain.

Answers: (a) Yes — the logic is valid. Squares have all rectangle properties (90° angles, equal diagonals) and rectangles have all parallelogram properties (opposite sides equal and parallel, diagonals bisect). (b) A square has all sides equal AND all angles 90° AND equal diagonals. A general parallelogram may have unequal sides, non-right angles, and unequal diagonals. (c) No — a rhombus has all sides equal but does NOT need all angles to be 90°. Only a rhombus with 90° angles is a square.

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