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A23: Generating Sequences

Foundation Higher AQAEdexcelOCREduqasCCEA

Generate terms of a sequence from term-to-term or position-to-term rules

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📋 Key Concepts

Sequence: An ordered list of numbers. Each number is called a term.
Two types of rules:
  • Term-to-term: How to get from one term to the next
  • Position-to-term: Formula for the nth term

📝 Term-to-Term Rules

Definition: A rule that tells you how to find the next term from the previous term.
Example 1

Generate the first 5 terms of a sequence starting with 3, where each term is found by adding 5.

Solution:

Start: 3

Add 5: 3 + 5 = 8

Add 5: 8 + 5 = 13

Add 5: 13 + 5 = 18

Add 5: 18 + 5 = 23

Sequence: 3, 8, 13, 18, 23, ...

Example 2

Generate the first 6 terms starting with 2, where each term is found by multiplying by 3.

Solution:

2, 6, 18, 54, 162, 486, ...

Example 3

A sequence starts 1, 4, 10, 22, ... Find the term-to-term rule.

Solution:

4 - 1 = 3

10 - 4 = 6

22 - 10 = 12

Differences: 3, 6, 12 (doubling each time)

Rule: Multiply by 2 and add 2

Check: 4 × 2 + 2 = 10 ✓, 10 × 2 + 2 = 22 ✓

📝 Position-to-Term Rules

Definition: A rule that gives the nth term directly. Written as a formula using n.
Notation:
  • n = position in sequence (1st, 2nd, 3rd, ...)
  • uₙ or aₙ = nth term
Example 4

Find the first 5 terms of the sequence where uₙ = 2n + 1

Solution:

u₁ = 2(1) + 1 = 3

u₂ = 2(2) + 1 = 5

u₃ = 2(3) + 1 = 7

u₄ = 2(4) + 1 = 9

u₅ = 2(5) + 1 = 11

Sequence: 3, 5, 7, 9, 11, ...

Example 5

Find the 10th term of the sequence uₙ = n² - 3

Solution:

u₁₀ = 10² - 3 = 100 - 3 = 97

📝 Finding a Specific Term

Example 6

The nth term of a sequence is 3n - 2. Find the 20th term.

Solution:

u₂₀ = 3(20) - 2 = 60 - 2 = 58

Example 7

Is 100 a term in the sequence uₙ = 4n + 7?

Solution:

Set 4n + 7 = 100

4n = 93

n = 23.25

n is not a whole number, so 100 is NOT in the sequence.

📝 Finding the Position of a Term

Example 8

The nth term is 5n - 3. Which term equals 47?

Solution:

5n - 3 = 47

5n = 50

n = 10

47 is the 10th term

❓ Practice Questions

Q1: Generate the first 5 terms starting at 2, adding 4 each time.

Q2: Generate the first 4 terms starting at 1, multiplying by 2 each time.

Q3: Find the first 5 terms where uₙ = 3n - 1.

Q4: Find the 15th term of uₙ = 2n + 5.

Q5: Is 50 a term in the sequence uₙ = 6n + 2?

Q6: Which term in the sequence uₙ = 7n - 4 equals 66?

✅ Answers

  1. 2, 6, 10, 14, 18
  2. 1, 2, 4, 8
  3. 2, 5, 8, 11, 14
  4. 35
  5. 6n + 2 = 50 → n = 8, so yes, 50 is the 8th term
  6. n = 10 (the 10th term)

🎯 Exam Tips

🧠 Problem-Solving Strategies

Problem-Solving

For term-to-term rules: look at differences or ratios between consecutive terms. For position-to-term rules: substitute the position number into the formula. To check if a number belongs, set the formula equal to it and solve — n must be a positive integer.
Multi-Step Problem

The nth term of a sequence is 4n - 3. (a) Find the first 4 terms. (b) Is 97 in the sequence? (c) Which term equals 97?

Solution:

(a) n=1: 1, n=2: 5, n=3: 9, n=4: 13

(b) Set 4n - 3 = 97 → 4n = 100 → n = 25. Yes, it's the 25th term.

(c) 97 is the 25th term

⚠️ Common Errors

Watch Out!

1. Wrong: Thinking the first term corresponds to n = 0 Correct: The first term always corresponds to n = 1

2. Wrong: Saying 50 is in the sequence 6n + 2 because 50 "looks right" Correct: Check algebraically: 6n + 2 = 50 → n = 8 (whole number), so yes it is the 8th term

3. Wrong: Confusing term-to-term with position-to-term rules Correct: Term-to-term tells how to get the next term; position-to-term gives a formula for any term directly

✍️ 6-Mark Exam Question

Extended Answer

6 marks: A sequence has nth term 5n + 3. (a) Find the 1st, 10th and 100th terms. (b) Is 2023 in the sequence? Show working. (c) Two consecutive terms add to 73. Which two terms are they?

(a) 1st: 5(1) + 3 = 8. 10th: 5(10) + 3 = 53. 100th: 5(100) + 3 = 503

(b) 5n + 3 = 2023 → 5n = 2020 → n = 404. Yes, it's the 404th term.

(c) Consecutive terms: (5n + 3) + (5(n+1) + 3) = 73 → 10n + 11 = 73 → 10n = 62 → n = 6.2. Not a whole number, so no two consecutive terms add to 73. Wait — let me recheck: 10n + 8 + 5 + 3 = 10n + 11. Hmm: (5n+3) + (5n+8) = 10n + 11 = 73 → n = 6.2. No integer solution. Actually this means 73 is not achievable.

Mark scheme: (a) 2 marks. (b) 2 marks with working. (c) 2 marks for correct method and conclusion.

📊 AO3: Reason & Interpret

Reasoning and Interpretation

A savings account adds £15 per month. In month 1 the balance is £35.

(a) Write a formula for the balance B in month n.

(b) When does the balance exceed £500?

(c) Explain why this model might not be realistic long-term.

Answers: (a) B = 35 + 15(n - 1) = 15n + 20. (b) 15n + 20 > 500 → n > 32. So from month 33. (c) The model ignores interest earned and inflation; in reality savings grow with compound interest, not just linear deposits.

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