G5: Congruence Criteria
Know and use the criteria for congruent triangles: SSS, SAS, ASA, RHS
Know and use the criteria for congruent triangles: SSS, SAS, ASA, RHS
Triangle ABC has sides AB = 5 cm, BC = 7 cm, AC = 4 cm. Triangle DEF has sides DE = 5 cm, EF = 7 cm, DF = 4 cm. Prove the triangles are congruent.
Solution:
AB = DE = 5 cm
BC = EF = 7 cm
AC = DF = 4 cm
All three corresponding sides are equal, so by SSS, triangles ABC and DEF are congruent.
In triangles PQR and XYZ: PQ = XY = 6 cm, QR = YZ = 8 cm, and angle PQR = angle XYZ = 45ยฐ. Prove the triangles are congruent.
Solution:
PQ = XY = 6 cm (first side)
Angle PQR = Angle XYZ = 45ยฐ (included angle)
QR = YZ = 8 cm (second side)
Two sides and the included angle are equal, so by SAS, triangles PQR and XYZ are congruent.
In triangles ABC and DEF: AB = DE = 5 cm, angle A = 50ยฐ, angle B = 60ยฐ, angle D = 50ยฐ, angle E = 60ยฐ. Prove congruence.
Solution:
Angle A = Angle D = 50ยฐ
AB = DE = 5 cm (included side)
Angle B = Angle E = 60ยฐ
Two angles and the included side are equal, so by ASA, triangles ABC and DEF are congruent.
Triangle ABC is right-angled at B. Triangle DEF is right-angled at E. AC = DF = 10 cm, AB = DE = 6 cm. Prove congruence.
Solution:
Both triangles are right-angled
AC = DF = 10 cm (hypotenuses are equal)
AB = DE = 6 cm (one pair of corresponding sides equal)
By RHS, triangles ABC and DEF are congruent.
Two triangles have angles of 40ยฐ, 60ยฐ, 80ยฐ. Are they congruent?
Solution: Not necessarily. They are similar (same angles) but could have different sizes. We need information about the sides to prove congruence.
Congruence = identical shape AND size. Four criteria: SSS, SAS, ASA (or AAS), RHS. AAA and SSA are NOT criteria.
Two triangles share: AB = DE = 6 cm, BC = EF = 8 cm, AC = DF = 10 cm. Congruent?
Yes โ SSS (all three pairs equal)
B1 with criterion named. Naming the criterion IS the marks โ a bare 'yes' does not score.
Why do two triangles with angles 30ยฐ, 60ยฐ, 90ยฐ but sides 3-4-5 and 6-8-10 fail congruence?
All angles match (AAA) but the sizes differ โ they are similar, not congruent.
B1 for the similarity distinction. AAA fixes shape but not scale โ the classic distractor.
Exam wording to expect: "prove/explain whether the triangles are congruent", name the criterion in every proof.
Q1: What does SSS stand for?
Q2: State the congruence criterion used when you know: two sides and the angle between them.
Q3: Why is AAA not a congruence criterion?
Q4: What does the H stand for in RHS?
Q5: Two right-angled triangles have hypotenuses of 13 cm and one side of 5 cm each. Are they congruent?
Q6: Triangles PQR and XYZ: PQ = XY = 7 cm, QR = YZ = 9 cm, angle PQR = angle XYZ = 50ยฐ. Are they congruent? Which criterion?
Q7: Two right-angled triangles have hypotenuse 13 and one leg 5 (each). Congruent? Criterion?
Every mark comes from the working, not just the answer. These model answers show the lines a mark scheme expects to see.
Q1. Side-Side-Side
Q2. SAS โ two sides and the angle BETWEEN them
Q3. AAA gives similar triangles (same shape, any size)
Q4. Hypotenuse
Q5. Yes โ RHS (right angle, hypotenuse, side)
Q6. Yes โ SAS: two pairs of equal sides with the included angle equal
Q7. Yes โ RHS (13, 5, and the right angle)
Congruence: 2โ4 marks on Paper 1. The criterion name is the marks โ the included-angle condition is what separates SAS from the SSA trap.
Links to: geometric proof (G6), similar shapes (G19), Pythagoras (G20).
Spec 8300. Three papers, each 80 marks and 1h30: Paper 1 non-calculator, Papers 2 and 3 calculator. Foundation/Higher tiers. Roughly a third of the marks sit under AO2 (reasoning) and AO3 (problem-solving), so show every line of working โ method marks survive arithmetic slips.
Always check: specification details change โ confirm paper structure and set texts against the current specification for your exam year.
Triangle ABC has AB = 8 cm, BC = 6 cm and โ ABC = 90ยฐ. Triangle PQR has PQ = 8 cm, QR = 6 cm and โ PQR = 90ยฐ. Prove the triangles are congruent and find AC if PR = 10 cm.
Solution: Both triangles have two sides and the included right angle equal: AB = PQ, BC = QR, โ ABC = โ PQR = 90ยฐ. By SAS (or RHS), the triangles are congruent. Since they are congruent, AC = PR = 10 cm.
1. Wrong: Using SSA to prove congruence (two sides and a non-included angle) Correct: SSA is NOT a congruence criterion โ it can produce two different triangles (the ambiguous case). Only use SSS, SAS, ASA, AAS, or RHS.
2. Wrong: Saying two triangles are congruent just because they have the same area Correct: Triangles with the same area can have completely different shapes. Congruence requires matching sides AND angles.
3. Wrong: For RHS, not checking that the angle is the right angle (not just any angle) Correct: RHS requires the Right angle, the Hypotenuse and one Side. The right angle must be explicitly stated or proven โ it cannot be assumed.
6 marks: In the diagram, AB = CD, AD = BC, and AC is a shared diagonal. (a) Prove that triangle ABC is congruent to triangle CDA. (b) Hence show that AB is parallel to DC. (c) What type of quadrilateral is ABCD? Justify your answer fully.
(a) In triangles ABC and CDA: AB = CD (given), BC = AD (given), AC is common. By SSS, โณABC โก โณCDA.
(b) Since the triangles are congruent, โ BAC = โ DCA (corresponding angles in congruent triangles). These are alternate angles formed by line AC crossing AB and DC. Since alternate angles are equal, AB is parallel to DC.
(c) ABCD is a parallelogram. We have shown AB โฅ DC. By a similar argument using the other pair of equal angles, AD โฅ BC. Both pairs of opposite sides are parallel, so it is a parallelogram.
Mark scheme: M1 identifying equal sides, A1 SSS congruence, M1 corresponding angles, A1 parallel lines reason, M1 other pair, A1 parallelogram justified
Two triangles each have sides of 5 cm and 7 cm with an angle of 40ยฐ.
(a) If the 40ยฐ angle is between the two sides in both triangles, are they congruent?
(b) If the 40ยฐ angle is NOT the included angle in both triangles, must they still be congruent?
(c) A student claims "If two triangles have the same three angles, they must be congruent." Give a counterexample to disprove this.
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