N3: Order of Operations
Use brackets, powers, roots and reciprocals; understand and use the conventions of BIDMAS/BODMAS
Use brackets, powers, roots and reciprocals; understand and use the conventions of BIDMAS/BODMAS
Calculate: 3 + 4 × 2
Solution:
Multiplication before addition: 4 × 2 = 8
Then: 3 + 8 = 11
Not 7 × 2 = 14 (wrong!)
Calculate: (3 + 4) × 2
Solution:
Brackets first: 3 + 4 = 7
Then: 7 × 2 = 14
Calculate: 20 - 12 ÷ 4 + 3
Solution:
Division first: 12 ÷ 4 = 3
Then left to right: 20 - 3 = 17
Finally: 17 + 3 = 20
Calculate: 5² - 3²
Solution:
Calculate powers: 5² = 25, 3² = 9
Then: 25 - 9 = 16
Calculate: √16 + 2³
Solution:
Roots and powers: √16 = 4, 2³ = 8
Then: 4 + 8 = 12
Calculate: 2 × (3 + 4)² - 10
Solution:
Step 1 - Brackets: 3 + 4 = 7
Step 2 - Indices: 7² = 49
Step 3 - Multiplication: 2 × 49 = 98
Step 4 - Subtraction: 98 - 10 = 88
Calculate: 48 ÷ 4 × 3 - 6
Solution:
Division and multiplication (left to right):
48 ÷ 4 = 12
12 × 3 = 36
Then subtraction: 36 - 6 = 30
Calculate: (12 - 4) ÷ 2 + 3 × 2²
Solution:
Brackets: 12 - 4 = 8
Indices: 2² = 4
Division: 8 ÷ 2 = 4
Multiplication: 3 × 4 = 12
Addition: 4 + 12 = 16
Calculate: -3² + 4 × 2
Solution:
Indices: -9 (the negative is not squared)
Multiplication: 4 × 2 = 8
Addition: -9 + 8 = -1
Q1: Calculate: 8 + 4 × 3
Q2: Calculate: (15 - 6) ÷ 3
Q3: Calculate: 2³ + 4² - 10
Q4: Calculate: 50 ÷ 5 × 2 + 3
Q5: Calculate: (2 + 3) × (8 - 4)²
Insert brackets to make this calculation correct: 3 + 4 × 5 − 2 = 33
Solution: Try (3 + 4) × 5 − 2 = 7 × 5 − 2 = 35 − 2 = 33 ✓. The brackets need to go around 3 + 4.
1. Wrong: 3 + 4 × 2 = 14 (working left to right) Correct: Multiplication first: 4 × 2 = 8, then 3 + 8 = 11
2. Wrong: -3² = 9 (squaring the negative) Correct: -3² = −(3²) = −9; it is NOT (−3)² = 9
3. Wrong: 12 ÷ 3 × 2 = 2 (doing multiplication first) Correct: Division and multiplication are equal priority — work left to right: 12 ÷ 3 = 4, then 4 × 2 = 8
6 marks: Two students evaluate 24 − 18 ÷ 3 + 2 × 5. Alice gets 4. Bob gets 28. (a) Show which student is correct. (b) Explain the mistake the other student made. (c) Use brackets in two different ways to make the answer equal to (i) 4 and (ii) 28.
(a) Correct BIDMAS: 18 ÷ 3 = 6, 2 × 5 = 10, then 24 − 6 + 10 = 28. Bob is correct.
(b) Alice did left to right: 24 − 18 = 6, 6 ÷ 3 = 2, 2 + 2 = 4, 4 × 5 = 20 — or similar, ignoring BIDMAS.
(c)(i) (24 − 18) ÷ (3 + 2) × 5 = 6 ÷ 5 × 5 = 6. Or: 24 − (18 ÷ (3 + 2)) × 5 = 24 − (18 ÷ 5) × 5 ≈ 6. To get exactly 4: (24 − 18 ÷ 3 + 2) × 5 needs adjustment. One way: 24 − (18 ÷ 3 + 2) × 5 = 24 − (6 + 2) × 5 = 24 − 40 = −16. Try: (24 − 18) ÷ 3 + 2 × 5 = 6 ÷ 3 + 10 = 2 + 10 = 12. For 4: ((24 − 18) ÷ 3 + 2) × 5 doesn't work. Correct: (24 − (18 ÷ 3 + 2 × 5)) = 24 − (6 + 10) = 8. For 4: (24 − 18) ÷ (3 + 2 × 5) = 6/13 — not 4. To get 4: (24 − 18 ÷ 3 + 2) is not 4... Let's try: 24 − (18 ÷ (3 + 2) × 5) = 24 − (18 ÷ 5 × 5) = 24 − 18 = 6. For exactly 4: (24 − 18) ÷ 3 + 2 = 4. (c)(ii) For 28, the original expression already gives 28 without brackets, but 24 − (18 ÷ 3) + (2 × 5) = 24 − 6 + 10 = 28.
Mark scheme: 2 marks for correct evaluation showing 28, 2 marks for clear explanation of the mistake, 2 marks for correct bracket placements
A teacher writes the expression 2 + 3² × 4 on the board. Two students disagree on the answer.
(a) Calculate the correct value.
(b) Student A says "The answer is 56 because I did 2 + 3 = 5, then 5² = 25, then 25 × 4 = 100." What mistake did Student A make?
(c) Where should brackets be placed to make Student A's answer of 100 correct? Justify your answer.
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