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N4: Prime Numbers, Factors & Multiples

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Prime numbers, factors, multiples, HCF, LCM, prime factorisation, product notation

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📋 Key Concepts

Prime Number: A number greater than 1 that has exactly two factors: 1 and itself.
First 20 Prime Numbers:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71
Remember: 1 is NOT a prime number. 2 is the only even prime number.

Definitions

TermDefinitionExample
FactorA number that divides exactly into another numberFactors of 12: 1, 2, 3, 4, 6, 12
MultipleThe result of multiplying a number by an integerMultiples of 5: 5, 10, 15, 20...
HCFHighest Common FactorHCF of 12 and 18 = 6
LCMLowest Common MultipleLCM of 4 and 6 = 12

📝 Finding Factors

Method: Find factor pairs by dividing. Work from 1 upwards until you meet in the middle.
Example 1

Find all factors of 24

Solution:

1 × 24 = 24 → factors: 1, 24

2 × 12 = 24 → factors: 2, 12

3 × 8 = 24 → factors: 3, 8

4 × 6 = 24 → factors: 4, 6

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

📝 Prime Factorisation

Method: Use a factor tree to break down a number into its prime factors. Write using index notation.
Example 2

Express 60 as a product of its prime factors

Solution:

     60
    /  \
   6    10
  / \   / \
 2   3 2   5

Prime factors: 2 × 2 × 3 × 5 = 2² × 3 × 5

Example 3

Express 84 as a product of its prime factors

Solution: 84 = 2² × 3 × 7

Check: 4 × 3 × 7 = 84 ✓

📝 Finding HCF

Method 1 - Lists: List all factors of each number and find the largest common one.
Method 2 - Prime Factors: Multiply together the common prime factors with their lowest powers.
Example 4

Find the HCF of 24 and 36

Solution (using prime factors):

24 = 2³ × 3

36 = 2² × 3²

Common factors: 2² × 3 = 12

HCF = 12

📝 Finding LCM

Method 1 - Lists: List multiples of each number until you find the first common one.
Method 2 - Prime Factors: Multiply together all prime factors with their highest powers.
Example 5

Find the LCM of 24 and 36

Solution (using prime factors):

24 = 2³ × 3

36 = 2² × 3²

LCM = 2³ × 3² = 8 × 9 = 72

📝 HCF and LCM Together

Useful relationship: For any two numbers a and b: HCF × LCM = a × b
Example 6

Two numbers have HCF = 4 and LCM = 60. If one number is 12, find the other.

Solution:

HCF × LCM = a × b

4 × 60 = 12 × b

240 = 12 × b

b = 240 ÷ 12 = 20

❓ Practice Questions

Q1: List all factors of 18

Q2: Express 72 as a product of its prime factors

Q3: Find the HCF of 28 and 42

Q4: Find the LCM of 8 and 12

Q5: Show that 87 is not a prime number

✅ Answers

  1. 1, 2, 3, 6, 9, 18
  2. 72 = 2³ × 3²
  3. 28 = 2² × 7, 42 = 2 × 3 × 7, HCF = 14
  4. LCM = 24 (or: 8 = 2³, 12 = 2² × 3, LCM = 2³ × 3 = 24)
  5. 87 = 3 × 29, so it has more than two factors

🎯 Exam Tips

🧠 Problem-Solving Strategies

Problem-Solving

For HCF/LCM word problems, identify whether the question asks about a "largest" shared quantity (HCF) or a "smallest" common time/event (LCM). Use prime factorisation for reliability — list methods miss factors. When checking, verify: HCF must divide into both numbers, and LCM must be divisible by both numbers.
Multi-Step Problem

Buses leave a station every 12 minutes and trains leave every 18 minutes. If a bus and a train both leave at 9:00 am, when is the next time they both leave together?

Solution: Find LCM of 12 and 18. 12 = 2² × 3, 18 = 2 × 3². LCM = 2² × 3² = 36 minutes. Next time = 9:00 + 36 min = 9:36 am.

⚠️ Common Errors

Watch Out!

1. Wrong: HCF uses highest powers of all prime factors Correct: HCF uses common prime factors with their LOWEST powers only

2. Wrong: LCM uses lowest powers of common prime factors Correct: LCM uses ALL prime factors with their HIGHEST powers

3. Wrong: 1 is a prime number Correct: 1 is NOT prime — it has only one factor, not two

✍️ 6-Mark Exam Question

Extended Answer

6 marks: (a) Express 120 and 180 as products of their prime factors. (b) Find the HCF and LCM of 120 and 180. (c) Two lighthouses flash every 120 seconds and 180 seconds. They flash together at midnight. How long will it be until they next flash together, and at what time will this be?

(a) 120 = 2³ × 3 × 5, 180 = 2² × 3² × 5

(b) HCF = 2² × 3 × 5 = 60. LCM = 2³ × 3² × 5 = 360.

(c) They flash together every LCM seconds = 360 seconds = 6 minutes. Time = 00:06 am.

Mark scheme: 2 marks for correct prime factorisations, 2 marks for HCF and LCM, 2 marks for converting to minutes and giving the time

📊 AO3: Reason & Interpret

Reasoning and Interpretation

A gardener has two rectangular plots. Plot A is 18 m by 24 m. Plot B is 30 m by 42 m. He wants to divide both plots into equal-sized square sections with no land wasted.

(a) What is the largest possible side length of the square sections for Plot A?

(b) He wants the same square size to work for both plots. Is this possible? Explain why.

(c) What is the largest square size that would work for both plots without wasting land?

Answers: (a) HCF of 18 and 24. 18 = 2 × 3², 24 = 2³ × 3. HCF = 2 × 3 = 6 m. (b) For Plot B, HCF of 30 and 42 = 6. So 6 m works for both! (c) The largest square is the HCF of all four numbers. Check: 6 divides 18, 24, 30, and 42. Yes — 6 m squares work for both plots.

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