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Complex Numbers
Exam Board: AQA Pearson Edexcel OCR WJEC / Eduqas CCEA
📌 Key Points
Key Fact: Cartesian form: z = a + bi; Polar form: z = r(cos θ + i sin θ) = re^{iθ}
Key Fact: Modulus |z| = sqrt(a^2+b^2); Argument arg(z) = arctan(b/a) (adjust for quadrant)
Key Fact: Conjugate: z̄ = a - bi = re^{-iθ}; Properties: z + z̄ = 2a, z z̄ = |z|^2
Key Fact: de Moivre: (cos θ + i sin θ)ⁿ = cos nθ + i sin nθ; (re^{iθ})ⁿ = rⁿe^{inθ}
Key Fact: n-th roots: r^{1/n} e^{i(θ+2kpi)/n} for k = 0,1,...,n-1 (n distinct roots)
Key Fact: Complex roots of real polynomials occur in conjugate pairs
Key Fact: Loci: |z - a| = r (circle), arg(z - a) = α (half-line), |z - a| = |z - b| (perp bisector)
Key Fact: Euler's formula: e^{iθ} = cos θ + i sin θ; cos θ = ½(e^{iθ}+e^{-iθ}), sin θ = (e^{iθ}-e^{-iθ})/(2i)
🎯 Learning Objectives
Perform arithmetic with complex numbers in cartesian and polar form Represent complex numbers on the Argand diagram Find modulus and argument of complex numbers Apply de Moivre's theorem for powers and roots Solve polynomial equations with complex roots Understand loci on the Argand diagram (circles, lines, half-lines) Use complex numbers to solve geometric problems
💡 Worked Example
Exam-Style Question
Question: Solve z^3 = -8. Plot the roots on an Argand diagram and show they form an equilateral triangle
Model Answer:
z^3 = 8e^{ipi} -> z = 2e^{i(pi+2kpi)/3} for k=0,1,2. Roots: 2e^{ipi/3} = 1+isqrt3, 2e^{ipi} = -2, 2e^{i5pi/3} = 1-isqrt3. Distance between any two = sqrt((1-(-2))^2+(sqrt3-0)^2) = sqrt(9+3) = 2sqrt3 -- all equal, equilateral triangle
❓ Practice Questions
Questions:
Express (1+isqrt3)⁶ in polar form Find all solutions to z⁴ = -16 Solve z^2 + 4z + 13 = 0, plot roots Show that |z-3| = 2|z+3| is a circle, find its centre and radius If z = cos θ + i sin θ, express cos 3θ in terms of cos θ
📄 Past Papers & Exam Resources
🔗 Further Reading & Resources
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