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Hyperbolic Functions
Exam Board: AQA Pearson Edexcel OCR WJEC / Eduqas CCEA
📌 Key Points
Key Fact: sinh x = (eˣ - e⁻ˣ)/2, cosh x = (eˣ + e⁻ˣ)/2, tanh x = sinh x/cosh x
Key Fact: Identities: cosh^2x - sinh^2x = 1, 1 - tanh^2x = sech^2x, sinh 2x = 2 sinh x cosh x, cosh 2x = cosh^2x + sinh^2x
Key Fact: Derivatives: d/dx(sinh x) = cosh x, d/dx(cosh x) = sinh x, d/dx(tanh x) = sech^2x
Key Fact: Integrals: ∫sinh x dx = cosh x + C, ∫cosh x dx = sinh x + C, ∫sech^2x dx = tanh x + C
Key Fact: Inverse functions: arsinh x = ln(x + sqrt(x^2+1)), arcosh x = ln(x + sqrt(x^2-1)) (x>=1), artanh x = ½ ln((1+x)/(1-x)) (|x|<1)
Key Fact: Osborn's rule: trig identity -> hyperbolic by changing sign of sin^2 terms
🎯 Learning Objectives
Define sinh, cosh, tanh, sech, cosech, coth in terms of exponentials Prove and use hyperbolic identities (analogous to trig identities) Differentiate and integrate hyperbolic functions Solve equations involving hyperbolic functions Use inverse hyperbolic functions and their logarithmic forms Apply hyperbolic functions to calculus problems (e.g. catenary)
💡 Worked Example
Exam-Style Question
Question: Solve 2 cosh x - 3 sinh x = 1
Model Answer:
2(eˣ+e⁻ˣ)/2 - 3(eˣ-e⁻ˣ)/2 = 1 -> eˣ+e⁻ˣ - 1.5(eˣ-e⁻ˣ) = 1 -> -0.5eˣ + 2.5e⁻ˣ = 1 -> multiply 2eˣ: -e^2ˣ + 5 = 2eˣ -> e^2ˣ + 2eˣ - 5 = 0 -> eˣ = -1 +/- sqrt6 -> eˣ = sqrt6 - 1 -> x = ln(sqrt6 - 1)
❓ Practice Questions
Questions:
Prove: cosh 2x = 2cosh^2x - 1 = 1 + 2sinh^2x ∫ sinh^2x dx Solve: tanh x = ½ Find arsinh(2) Show that the catenary y = cosh x has arc length ∫cosh x dx from a to b
📄 Past Papers & Exam Resources
🔗 Further Reading & Resources
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